一、口算。
$120\% ÷ \frac{4}{9} =$
$\frac{5}{3} ÷ 5 =$
$\frac{7}{15} × \frac{3}{7} =$
$\frac{3}{4} - \frac{2}{7} =$
$\frac{2}{7} × 2.1 =$
$\frac{1}{6} ÷ \frac{7}{6} =$
$\frac{3}{4} ÷ \frac{2}{3} =$
$4.6 × 10\% =$
$\frac{1}{5} + \frac{7}{40} =$
$\frac{5}{9} × \frac{3}{5} =$
$\frac{3}{5} - \frac{3}{7} =$
$20\% + \frac{1}{4} =$
$\frac{5}{6} × 36\% =$
$\frac{2}{3} × \frac{3}{7} =$
$10 ÷ \frac{5}{24} =$
$\frac{7}{16} ÷ \frac{1}{4} =$
$0.23 ÷ 1\% =$
$\frac{9}{32} ÷ \frac{3}{4} =$
$\frac{3}{4} × \frac{16}{15} =$
$\frac{1}{2} + \frac{1}{5} =$
$\frac{2}{9} ÷ \frac{1}{2} =$
$120\% ÷ \frac{4}{9} =$
$\frac{5}{3} ÷ 5 =$
$\frac{7}{15} × \frac{3}{7} =$
$\frac{3}{4} - \frac{2}{7} =$
$\frac{2}{7} × 2.1 =$
$\frac{1}{6} ÷ \frac{7}{6} =$
$\frac{3}{4} ÷ \frac{2}{3} =$
$4.6 × 10\% =$
$\frac{1}{5} + \frac{7}{40} =$
$\frac{5}{9} × \frac{3}{5} =$
$\frac{3}{5} - \frac{3}{7} =$
$20\% + \frac{1}{4} =$
$\frac{5}{6} × 36\% =$
$\frac{2}{3} × \frac{3}{7} =$
$10 ÷ \frac{5}{24} =$
$\frac{7}{16} ÷ \frac{1}{4} =$
$0.23 ÷ 1\% =$
$\frac{9}{32} ÷ \frac{3}{4} =$
$\frac{3}{4} × \frac{16}{15} =$
$\frac{1}{2} + \frac{1}{5} =$
$\frac{2}{9} ÷ \frac{1}{2} =$
答案
1.$2.7$
2.$\frac{1}{3}$
3.$\frac{1}{5}$
4.$\frac{13}{28}$
5.$0.6$
6.$\frac{1}{7}$
7.$\frac{9}{8}$
8.$0.46$
9.$\frac{3}{8}$
10.$\frac{1}{3}$
11.$\frac{6}{35}$
12.$\frac{9}{20}$
13.$0.3$
14.$\frac{2}{7}$
15.$48$
16.$\frac{7}{4}$
17.$23$
18.$\frac{3}{8}$
19.$\frac{4}{5}$
20.$\frac{7}{10}$
21.$\frac{4}{9}$
2.$\frac{1}{3}$
3.$\frac{1}{5}$
4.$\frac{13}{28}$
5.$0.6$
6.$\frac{1}{7}$
7.$\frac{9}{8}$
8.$0.46$
9.$\frac{3}{8}$
10.$\frac{1}{3}$
11.$\frac{6}{35}$
12.$\frac{9}{20}$
13.$0.3$
14.$\frac{2}{7}$
15.$48$
16.$\frac{7}{4}$
17.$23$
18.$\frac{3}{8}$
19.$\frac{4}{5}$
20.$\frac{7}{10}$
21.$\frac{4}{9}$
二、计算下面各题,能用简便算法的就用简便算法。
$35×(1-\frac{4}{7})÷\frac{5}{16}$
$\frac{4}{5}×\frac{8}{7}+\frac{6}{7}÷125\%$
$1-(\frac{7}{12}-50\%)÷12.5\%$
$(\frac{7}{12}+\frac{11}{18})÷\frac{5}{36}$
$\frac{19}{15}-(65\%+\frac{4}{15})$
$10÷(\frac{1}{2}-\frac{1}{5}+\frac{1}{10})$
$35×(1-\frac{4}{7})÷\frac{5}{16}$
$\frac{4}{5}×\frac{8}{7}+\frac{6}{7}÷125\%$
$1-(\frac{7}{12}-50\%)÷12.5\%$
$(\frac{7}{12}+\frac{11}{18})÷\frac{5}{36}$
$\frac{19}{15}-(65\%+\frac{4}{15})$
$10÷(\frac{1}{2}-\frac{1}{5}+\frac{1}{10})$
答案
1.$48$
2.$\frac{8}{5}$
3.$\frac{1}{3}$
4.$\frac{43}{5}$
5.$0.35$
6.$25$
2.$\frac{8}{5}$
3.$\frac{1}{3}$
4.$\frac{43}{5}$
5.$0.35$
6.$25$
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