一 计算下面各题。
应用 “$\dfrac{b}{a} ÷ \dfrac{d}{c} = \dfrac{bc}{ac} ÷ \dfrac{da}{ca} = bc ÷ da = \dfrac{bc}{da}$($a$,$c$,$d$ 均不为 0)” 计算下面各题。
$\dfrac{5}{8} ÷ \dfrac{3}{4} =$
$\dfrac{11}{15} ÷ \dfrac{1}{3} =$
$\dfrac{7}{18} ÷ \dfrac{19}{6} =$
$\dfrac{3}{11} ÷ \dfrac{5}{22} =$
应用 “$\dfrac{b}{a} ÷ \dfrac{d}{c} = \dfrac{bc}{ac} ÷ \dfrac{da}{ca} = bc ÷ da = \dfrac{bc}{da}$($a$,$c$,$d$ 均不为 0)” 计算下面各题。
$\dfrac{5}{8} ÷ \dfrac{3}{4} =$
$\dfrac{11}{15} ÷ \dfrac{1}{3} =$
$\dfrac{7}{18} ÷ \dfrac{19}{6} =$
$\dfrac{3}{11} ÷ \dfrac{5}{22} =$
答案
1. $\dfrac{5}{8} ÷ \dfrac{3}{4} =\dfrac{5×4}{8×4}÷\dfrac{3×8}{4×8}=(5×4)÷(3×8)=\dfrac{5×4}{3×8}=\dfrac{5}{6}$
2. $\dfrac{11}{15} ÷ \dfrac{1}{3} =\dfrac{11×3}{15×3}÷\dfrac{1×15}{3×15}=(11×3)÷(1×15)=\dfrac{11×3}{1×15}=\dfrac{11}{5}$
3. $\dfrac{7}{18} ÷ \dfrac{19}{6} =\dfrac{7×6}{18×6}÷\dfrac{19×18}{6×18}=(7×6)÷(19×18)=\dfrac{7×6}{19×18}=\dfrac{7}{57}$
4. $\dfrac{3}{11} ÷ \dfrac{5}{22} =\dfrac{3×22}{11×22}÷\dfrac{5×11}{22×11}=(3×22)÷(5×11)=\dfrac{3×22}{5×11}=\dfrac{6}{5}$
2. $\dfrac{11}{15} ÷ \dfrac{1}{3} =\dfrac{11×3}{15×3}÷\dfrac{1×15}{3×15}=(11×3)÷(1×15)=\dfrac{11×3}{1×15}=\dfrac{11}{5}$
3. $\dfrac{7}{18} ÷ \dfrac{19}{6} =\dfrac{7×6}{18×6}÷\dfrac{19×18}{6×18}=(7×6)÷(19×18)=\dfrac{7×6}{19×18}=\dfrac{7}{57}$
4. $\dfrac{3}{11} ÷ \dfrac{5}{22} =\dfrac{3×22}{11×22}÷\dfrac{5×11}{22×11}=(3×22)÷(5×11)=\dfrac{3×22}{5×11}=\dfrac{6}{5}$
二 计算下面各题,能用简便算法的就用简便算法。
$\frac{11}{39}×\frac{4}{7}×13$
$24÷\frac{3}{4}×\frac{5}{8}$
$\frac{9}{10}×\frac{7}{8}-\frac{7}{8}×\frac{1}{10}$
$\frac{5}{6}÷(\frac{7}{12}÷\frac{14}{15})$
$(\frac{3}{4}-\frac{5}{24})÷\frac{1}{24}$
$\frac{4}{13}÷\frac{3}{7}+\frac{9}{13}÷\frac{3}{7}$
$\frac{11}{39}×\frac{4}{7}×13$
$24÷\frac{3}{4}×\frac{5}{8}$
$\frac{9}{10}×\frac{7}{8}-\frac{7}{8}×\frac{1}{10}$
$\frac{5}{6}÷(\frac{7}{12}÷\frac{14}{15})$
$(\frac{3}{4}-\frac{5}{24})÷\frac{1}{24}$
$\frac{4}{13}÷\frac{3}{7}+\frac{9}{13}÷\frac{3}{7}$
答案
1. $\frac{11}{39}×\frac{4}{7}×13=\frac{44}{21}$
2. $24÷\frac{3}{4}×\frac{5}{8}=20$
3. $\frac{9}{10}×\frac{7}{8}-\frac{7}{8}×\frac{1}{10}=\frac{7}{10}$
4. $\frac{5}{6}÷(\frac{7}{12}÷\frac{14}{15})=\frac{4}{3}$
5. $(\frac{3}{4}-\frac{5}{24})÷\frac{1}{24}=13$
6. $\frac{4}{13}÷\frac{3}{7}+\frac{9}{13}÷\frac{3}{7}=\frac{7}{3}$
2. $24÷\frac{3}{4}×\frac{5}{8}=20$
3. $\frac{9}{10}×\frac{7}{8}-\frac{7}{8}×\frac{1}{10}=\frac{7}{10}$
4. $\frac{5}{6}÷(\frac{7}{12}÷\frac{14}{15})=\frac{4}{3}$
5. $(\frac{3}{4}-\frac{5}{24})÷\frac{1}{24}=13$
6. $\frac{4}{13}÷\frac{3}{7}+\frac{9}{13}÷\frac{3}{7}=\frac{7}{3}$
1. 五(1)班有学生 45 人,参加社团活动的人数占全班的$\frac{3}{5}$,其中男生人数占参加社团活动人数的$\frac{1}{3}$。五(1)班参加社团活动的男生有多少人?
答案
$45×\frac{3}{5}×\frac{1}{3}=9$(人)
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