1. 口算。(建议用时3分钟)
$\frac{1}{3} × 12.5\% =$
$\frac{5}{11} ÷ \frac{6}{11} =$
$80\% ÷ 16\% × 10 =$
$64 ÷ 8\% =$
$\frac{5}{6} × 48\% =$
$25 × (1 + 20\%) =$
$\frac{4}{5} ÷ 60\% =$
$16\% ÷ 64\% =$
$560 × (1 - 37.5\%) =$
$\frac{8}{9} × \frac{6}{5} =$
$\frac{4}{15} × 150\% =$
$0.7 ÷ 35\% × 5 =$
$\frac{9}{11} × \frac{5}{18} =$
$12 ÷ \frac{5}{6} =$
$4.8 ÷ (1.6 - 80\%) =$
$\frac{3}{7} ÷ 50\% =$
$3 × \frac{3}{8} =$
$7.2 ÷ 0.6 × 30\% =$
$\frac{1}{3} × 12.5\% =$
$\frac{5}{11} ÷ \frac{6}{11} =$
$80\% ÷ 16\% × 10 =$
$64 ÷ 8\% =$
$\frac{5}{6} × 48\% =$
$25 × (1 + 20\%) =$
$\frac{4}{5} ÷ 60\% =$
$16\% ÷ 64\% =$
$560 × (1 - 37.5\%) =$
$\frac{8}{9} × \frac{6}{5} =$
$\frac{4}{15} × 150\% =$
$0.7 ÷ 35\% × 5 =$
$\frac{9}{11} × \frac{5}{18} =$
$12 ÷ \frac{5}{6} =$
$4.8 ÷ (1.6 - 80\%) =$
$\frac{3}{7} ÷ 50\% =$
$3 × \frac{3}{8} =$
$7.2 ÷ 0.6 × 30\% =$
答案
1. $\frac{1}{24}$
$\frac{5}{6}$
50
800
0.4
30
$\frac{4}{3}$
$\frac{1}{4}$
350
$\frac{16}{15}$
0.4
10
$\frac{5}{22}$
$\frac{72}{5}$
6
$\frac{6}{7}$
$\frac{9}{8}$
3.6
$\frac{5}{6}$
50
800
0.4
30
$\frac{4}{3}$
$\frac{1}{4}$
350
$\frac{16}{15}$
0.4
10
$\frac{5}{22}$
$\frac{72}{5}$
6
$\frac{6}{7}$
$\frac{9}{8}$
3.6
2. 把下面各数改写成百分数。(除不尽的百分号前保留一位小数)(建议用时2分钟)
1=(
0.015=(
0.8=(
1.36=(
$\frac{1}{8}$=(
$\frac{5}{7}$≈(
1=(
100
)%0.015=(
1.5
)%0.8=(
80
)%1.36=(
136
)%$\frac{1}{8}$=(
12.5
)%$\frac{5}{7}$≈(
71.4
)%答案
2. 100
1.5
80
136
12.5
71.4
1.5
80
136
12.5
71.4
3. 计算下面各题,能用简便算法的就用简便算法。(建议用时2分钟)
$3.6×2.5÷48\%$ $180×20\%×(1-30\%)$ $(48×\frac{3}{4}+64)÷25\%$
$3.6×2.5÷48\%$ $180×20\%×(1-30\%)$ $(48×\frac{3}{4}+64)÷25\%$
答案
3. 18.75
25.2
400
25.2
400
4. 解决问题。(建议用时3分钟)
某商品的售价是按进价提高五成定价的,打出“八折优惠酬宾”的广告后,每件商品仍可获利240元。该商品的进价是多少元?
某商品的售价是按进价提高五成定价的,打出“八折优惠酬宾”的广告后,每件商品仍可获利240元。该商品的进价是多少元?
答案
4. $240÷[(1+50\%)×80\%-1]=1200$(元)
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