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例4（山东·济南）计算：$(-2)^3 × \{ (-3) × [ (-5)^2 + 2 × (0.3 - \frac{3}{10}) ÷ 83 - 3 ] + 4^3 \}$.
解：$(-2)^3 × \{ (-3) × [ (-5)^2 + 2 × (0.3 - \frac{3}{10}) ÷ 83 - 3 ] + 4^3 \}$
$= -8 × [ (-3) × (25 + 0 - 3) + 64 ]$
$= -8 × [ (-3) × 22 + 64 ]$
$= -8 × (-66 + 64)$
$= -8 × (-2)$
$= 16$.
当题目中的括号形式比较复杂时，按小括号、中括号、大括号的顺序依次进行运算.
解：$(-2)^3 × \{ (-3) × [ (-5)^2 + 2 × (0.3 - \frac{3}{10}) ÷ 83 - 3 ] + 4^3 \}$
$= -8 × [ (-3) × (25 + 0 - 3) + 64 ]$
$= -8 × [ (-3) × 22 + 64 ]$
$= -8 × (-66 + 64)$
$= -8 × (-2)$
$= 16$.
当题目中的括号形式比较复杂时，按小括号、中括号、大括号的顺序依次进行运算.
答案
解：
$\begin{aligned}&(-2)^3 × \{ (-3) × [ (-5)^2 + 2 × (0.3 - \frac{3}{10}) ÷ 83 - 3 ] + 4^3 \} \\=&-8 × \{ (-3) × [ 25 + 2 × 0 ÷ 83 - 3 ] + 64 \} \\=&-8 × [ (-3) × (25 + 0 - 3) + 64 ] \\=&-8 × [ (-3) × 22 + 64 ] \\=&-8 × (-66 + 64) \\=&-8 × (-2) \\=&16\end{aligned}$
$\begin{aligned}&(-2)^3 × \{ (-3) × [ (-5)^2 + 2 × (0.3 - \frac{3}{10}) ÷ 83 - 3 ] + 4^3 \} \\=&-8 × \{ (-3) × [ 25 + 2 × 0 ÷ 83 - 3 ] + 64 \} \\=&-8 × [ (-3) × (25 + 0 - 3) + 64 ] \\=&-8 × [ (-3) × 22 + 64 ] \\=&-8 × (-66 + 64) \\=&-8 × (-2) \\=&16\end{aligned}$
