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计算
$1\dfrac{1}{2}×1\dfrac{1}{3}×1\dfrac{1}{4}×1\dfrac{1}{5}×···×1\dfrac{1}{50}$
算式中的分数都是带分数，将带分数先转化成假分数，再分别约分。
$1\dfrac{1}{2}×1\dfrac{1}{3}×1\dfrac{1}{4}×1\dfrac{1}{5}×···×1\dfrac{1}{50}$
$=\dfrac{51}{2}$
$1\dfrac{1}{2}×1\dfrac{1}{3}×1\dfrac{1}{4}×1\dfrac{1}{5}×···×1\dfrac{1}{50}$
算式中的分数都是带分数，将带分数先转化成假分数，再分别约分。
$1\dfrac{1}{2}×1\dfrac{1}{3}×1\dfrac{1}{4}×1\dfrac{1}{5}×···×1\dfrac{1}{50}$
$=\dfrac{51}{2}$
答案
$\dfrac{51}{2}$
计算。
$1\frac{1}{5}×1\frac{1}{6}×1\frac{1}{7}×1\frac{1}{8}×\dots×1\frac{1}{2025}$
$(1-\frac{1}{2})×(1-\frac{1}{3})×(1-\frac{1}{4})×\dots×(1-\frac{1}{2026})$
$1\frac{1}{5}×1\frac{1}{6}×1\frac{1}{7}×1\frac{1}{8}×\dots×1\frac{1}{2025}$
$(1-\frac{1}{2})×(1-\frac{1}{3})×(1-\frac{1}{4})×\dots×(1-\frac{1}{2026})$
答案
1.$\dfrac{2026}{5}$
2.$\dfrac{1}{2026}$
2.$\dfrac{1}{2026}$
