一、口算。
$560 ÷ 20 =$
$0.91 ÷ 13 =$
$2.4 - 0.15 =$
$4.25 + 0.75 =$
$1.54 ÷ 0.2 =$
$106 × 5 =$
$9.5 ÷ 0.5 =$
$8.8 + 0.12 =$
$540 - 170 =$
$129 + 345 =$
$36 × 30 =$
$1.01 - 0.11 =$
$12.5 × 6 =$
$690 ÷ 230 =$
$800 × 20 =$
$\frac{4}{5} + \frac{1}{4} =$
$\frac{4}{9} × \frac{1}{6} =$
$\frac{5}{7} ÷ \frac{5}{14} =$
$\frac{7}{3} ÷ \frac{7}{10} =$
$\frac{3}{4} - \frac{7}{10} =$
$\frac{7}{8} ÷ \frac{2}{3} =$
$\frac{4}{7} × \frac{7}{4} =$
$\frac{5}{7} + \frac{1}{2} =$
$\frac{2}{9} + \frac{7}{12} =$
$560 ÷ 20 =$
$0.91 ÷ 13 =$
$2.4 - 0.15 =$
$4.25 + 0.75 =$
$1.54 ÷ 0.2 =$
$106 × 5 =$
$9.5 ÷ 0.5 =$
$8.8 + 0.12 =$
$540 - 170 =$
$129 + 345 =$
$36 × 30 =$
$1.01 - 0.11 =$
$12.5 × 6 =$
$690 ÷ 230 =$
$800 × 20 =$
$\frac{4}{5} + \frac{1}{4} =$
$\frac{4}{9} × \frac{1}{6} =$
$\frac{5}{7} ÷ \frac{5}{14} =$
$\frac{7}{3} ÷ \frac{7}{10} =$
$\frac{3}{4} - \frac{7}{10} =$
$\frac{7}{8} ÷ \frac{2}{3} =$
$\frac{4}{7} × \frac{7}{4} =$
$\frac{5}{7} + \frac{1}{2} =$
$\frac{2}{9} + \frac{7}{12} =$
答案
1. 28
2. 0.07
3. 2.25
4. 5
5. 7.7
6. 530
7. 19
8. 8.92
9. 370
10. 474
11. 1080
12. 0.9
13. 75
14. 3
15. 16000
16. $\frac{21}{20}$
17. $\frac{2}{27}$
18. 2
19. $\frac{10}{3}$
20. $\frac{1}{20}$
21. $\frac{21}{16}$
22. 1
23. $\frac{17}{14}$
24. $\frac{29}{36}$
2. 0.07
3. 2.25
4. 5
5. 7.7
6. 530
7. 19
8. 8.92
9. 370
10. 474
11. 1080
12. 0.9
13. 75
14. 3
15. 16000
16. $\frac{21}{20}$
17. $\frac{2}{27}$
18. 2
19. $\frac{10}{3}$
20. $\frac{1}{20}$
21. $\frac{21}{16}$
22. 1
23. $\frac{17}{14}$
24. $\frac{29}{36}$
二、计算下面各题,能简算的要简算。
$(\frac{1}{8} + \frac{3}{4}) × (1 - \frac{1}{3})$
$(1 - \frac{8}{15} × \frac{1}{2}) ÷ \frac{4}{5}$
$\frac{1}{8} × 125 + \frac{1}{8} × 42 + \frac{1}{8}$
$5.5 × 17.3 + 6.7 × 5.5$
$7.74 × [2.8 - (1.3 + 1.5)]$
$7.5 + (32.4 - 11.6) ÷ 0.64$
$(\frac{1}{8} + \frac{3}{4}) × (1 - \frac{1}{3})$
$(1 - \frac{8}{15} × \frac{1}{2}) ÷ \frac{4}{5}$
$\frac{1}{8} × 125 + \frac{1}{8} × 42 + \frac{1}{8}$
$5.5 × 17.3 + 6.7 × 5.5$
$7.74 × [2.8 - (1.3 + 1.5)]$
$7.5 + (32.4 - 11.6) ÷ 0.64$
答案
1. $\frac{7}{12}$
2. $\frac{11}{12}$
3. 21
4. 132
5. 0
6. 40
2. $\frac{11}{12}$
3. 21
4. 132
5. 0
6. 40
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