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三、计算下面各题,怎样简便就怎样计算。
$\frac {3}{5}×\frac {1}{6}-\frac {1}{2}÷5$
$\frac {3}{7}-\frac {2}{5}+\frac {18}{7}-\frac {8}{5}$
$\frac {9}{16}÷\frac {1}{15}+\frac {7}{16}×15$
$\frac {4}{5}×\frac {4}{7}×\frac {5}{4}-\frac {1}{2}$
$\frac {4}{5}×\frac {5}{6}+\frac {2}{5}÷\frac {3}{5}$
$\frac {5}{6}×\frac {5}{8}+\frac {3}{8}÷\frac {6}{5}$
$4-\frac {8}{25}×\frac {15}{4}-\frac {4}{5}$
$\frac {12}{15}×(\frac {5}{6}-\frac {3}{4})+\frac {4}{5}$
$(\frac {7}{11}-\frac {1}{4})×44$
$\frac {1}{4}÷(1-\frac {1}{2}+\frac {1}{4})$
$(3-\frac {5}{11}-\frac {6}{11})÷\frac {8}{9}$
$15-48×(\frac {1}{12}+\frac {3}{16})$
$\frac {8}{13}÷7+\frac {1}{7}×\frac {6}{13}$
$\frac {2}{3}×[(\frac {3}{4}-\frac {1}{6})÷\frac {1}{5}]$
$\frac {12}{13}×\frac {5}{6}+\frac {1}{6}×\frac {12}{13}+\frac {12}{13}$
$\frac {3}{5}×\frac {1}{6}-\frac {1}{2}÷5$
$\frac {3}{7}-\frac {2}{5}+\frac {18}{7}-\frac {8}{5}$
$\frac {9}{16}÷\frac {1}{15}+\frac {7}{16}×15$
$\frac {4}{5}×\frac {4}{7}×\frac {5}{4}-\frac {1}{2}$
$\frac {4}{5}×\frac {5}{6}+\frac {2}{5}÷\frac {3}{5}$
$\frac {5}{6}×\frac {5}{8}+\frac {3}{8}÷\frac {6}{5}$
$4-\frac {8}{25}×\frac {15}{4}-\frac {4}{5}$
$\frac {12}{15}×(\frac {5}{6}-\frac {3}{4})+\frac {4}{5}$
$(\frac {7}{11}-\frac {1}{4})×44$
$\frac {1}{4}÷(1-\frac {1}{2}+\frac {1}{4})$
$(3-\frac {5}{11}-\frac {6}{11})÷\frac {8}{9}$
$15-48×(\frac {1}{12}+\frac {3}{16})$
$\frac {8}{13}÷7+\frac {1}{7}×\frac {6}{13}$
$\frac {2}{3}×[(\frac {3}{4}-\frac {1}{6})÷\frac {1}{5}]$
$\frac {12}{13}×\frac {5}{6}+\frac {1}{6}×\frac {12}{13}+\frac {12}{13}$
答案
$\frac{3}{5}×\frac{1}{6}-\frac{1}{2}÷5$
$=\frac{1}{10}-\frac{1}{10}$
$=0$
$\frac{3}{7}-\frac{2}{5}+\frac{18}{7}-\frac{8}{5}$
$=(\frac{3}{7}+\frac{18}{7})-(\frac{2}{5}+\frac{8}{5})$
$=3-2$
$=1$
$\frac{9}{16}÷\frac{1}{15}+\frac{7}{16}×15$
$=(\frac{9}{16}+\frac{7}{16})×15$
$=1×15$
$=15$
$\frac{4}{5}×\frac{4}{7}×\frac{5}{4}-\frac{1}{2}$
$=\frac{4}{7}-\frac{1}{2}$
$=\frac{1}{14}$
$\frac{4}{5}×\frac{5}{6}+\frac{2}{5}÷\frac{3}{5}$
$=\frac{2}{3}+\frac{2}{3}$
$=\frac{4}{3}$
$\frac{5}{6}×\frac{5}{8}+\frac{3}{8}÷\frac{6}{5}$
$=\frac{5}{6}×(\frac{5}{8}+\frac{3}{8})$
$=\frac{5}{6}×1$
$=\frac{5}{6}$
$4-\frac{8}{25}×\frac{15}{4}-\frac{4}{5}$
$=4-\frac{6}{5}-\frac{4}{5}$
$=4-2$
$=2$
$\frac{12}{15}×(\frac{5}{6}-\frac{3}{4})+\frac{4}{5}$
$=\frac{12}{15}×\frac{1}{12}+\frac{4}{5}$
$=\frac{1}{15}+\frac{12}{15}$
$=\frac{13}{15}$
$(\frac{7}{11}-\frac{1}{4})×44$
$=\frac{7}{11}×44-\frac{1}{4}×44$
$=28-11$
$=17$
$\frac{1}{4}÷(1-\frac{1}{2}+\frac{1}{4})$
$=\frac{1}{4}÷\frac{3}{4}$
$=\frac{1}{3}$
$(3-\frac{5}{11}-\frac{6}{11})÷\frac{8}{9}$
$=2÷\frac{8}{9}$
$=\frac{9}{4}$
$15-48×(\frac{1}{12}+\frac{3}{16})$
$=15-(4+9)$
$=15-13$
$=2$
$\frac{8}{13}÷7+\frac{1}{7}×\frac{6}{13}$
$=\frac{1}{7}×(\frac{8}{13}+\frac{6}{13})$
$=\frac{1}{7}×\frac{14}{13}$
$=\frac{2}{13}$
$\frac{2}{3}×[(\frac{3}{4}-\frac{1}{6})÷\frac{1}{5}]$
$=\frac{2}{3}×[\frac{7}{12}÷\frac{1}{5}]$
$=\frac{2}{3}×\frac{35}{12}$
$=\frac{35}{18}$
$\frac{12}{13}×\frac{5}{6}+\frac{1}{6}×\frac{12}{13}+\frac{12}{13}$
$=\frac{12}{13}×(\frac{5}{6}+\frac{1}{6}+1)$
$=\frac{12}{13}×2$
$=\frac{24}{13}$
$=\frac{1}{10}-\frac{1}{10}$
$=0$
$\frac{3}{7}-\frac{2}{5}+\frac{18}{7}-\frac{8}{5}$
$=(\frac{3}{7}+\frac{18}{7})-(\frac{2}{5}+\frac{8}{5})$
$=3-2$
$=1$
$\frac{9}{16}÷\frac{1}{15}+\frac{7}{16}×15$
$=(\frac{9}{16}+\frac{7}{16})×15$
$=1×15$
$=15$
$\frac{4}{5}×\frac{4}{7}×\frac{5}{4}-\frac{1}{2}$
$=\frac{4}{7}-\frac{1}{2}$
$=\frac{1}{14}$
$\frac{4}{5}×\frac{5}{6}+\frac{2}{5}÷\frac{3}{5}$
$=\frac{2}{3}+\frac{2}{3}$
$=\frac{4}{3}$
$\frac{5}{6}×\frac{5}{8}+\frac{3}{8}÷\frac{6}{5}$
$=\frac{5}{6}×(\frac{5}{8}+\frac{3}{8})$
$=\frac{5}{6}×1$
$=\frac{5}{6}$
$4-\frac{8}{25}×\frac{15}{4}-\frac{4}{5}$
$=4-\frac{6}{5}-\frac{4}{5}$
$=4-2$
$=2$
$\frac{12}{15}×(\frac{5}{6}-\frac{3}{4})+\frac{4}{5}$
$=\frac{12}{15}×\frac{1}{12}+\frac{4}{5}$
$=\frac{1}{15}+\frac{12}{15}$
$=\frac{13}{15}$
$(\frac{7}{11}-\frac{1}{4})×44$
$=\frac{7}{11}×44-\frac{1}{4}×44$
$=28-11$
$=17$
$\frac{1}{4}÷(1-\frac{1}{2}+\frac{1}{4})$
$=\frac{1}{4}÷\frac{3}{4}$
$=\frac{1}{3}$
$(3-\frac{5}{11}-\frac{6}{11})÷\frac{8}{9}$
$=2÷\frac{8}{9}$
$=\frac{9}{4}$
$15-48×(\frac{1}{12}+\frac{3}{16})$
$=15-(4+9)$
$=15-13$
$=2$
$\frac{8}{13}÷7+\frac{1}{7}×\frac{6}{13}$
$=\frac{1}{7}×(\frac{8}{13}+\frac{6}{13})$
$=\frac{1}{7}×\frac{14}{13}$
$=\frac{2}{13}$
$\frac{2}{3}×[(\frac{3}{4}-\frac{1}{6})÷\frac{1}{5}]$
$=\frac{2}{3}×[\frac{7}{12}÷\frac{1}{5}]$
$=\frac{2}{3}×\frac{35}{12}$
$=\frac{35}{18}$
$\frac{12}{13}×\frac{5}{6}+\frac{1}{6}×\frac{12}{13}+\frac{12}{13}$
$=\frac{12}{13}×(\frac{5}{6}+\frac{1}{6}+1)$
$=\frac{12}{13}×2$
$=\frac{24}{13}$
