4. 如图,一只蚂蚁从点 A沿数轴向右直爬2个单位长度到达点 B,点 A表示 $ -\sqrt{2} $ ,设点 B所表示的数为 m.
(2) 求 $ | m-1 |+( m+\sqrt{2} )^{2} $的值. (1) 求 m的值;
(2) 求 $ | m-1 |+( m+\sqrt{2} )^{2} $的值. (1) 求 m的值;
答案
4. (1)$m=-\sqrt{2}+2$ (2)$|m-1|+(m+\sqrt{2})^{2}=|-\sqrt{2}+2-1|+(-\sqrt{2}+2+\sqrt{2})^{2}=|-\sqrt{2}+1|+2^{2}=\sqrt{2}+3$
1. 由9个边长均为1的小正方形组成的图形如图所示,沿图的虚线 AB,BC,CD,DA裁剪,剪成一个小正方形ABCD. 
(1) 在图 $ \textcircled{1} $中,剪成的小正方形 ABCD的面积为_______,边 AB的长为_______;
(2) 现将图 $ \textcircled{1} $水平放置在如图 $ \textcircled{2} $所示的数轴上,使得小正方形的顶点 A与数轴上表示1的点重合。若以点 A为圆心,边 DA的长为半径画圆,与数轴交于点 E,求点 E表示的数.
(1) 在图 $ \textcircled{1} $中,剪成的小正方形 ABCD的面积为_______,边 AB的长为_______;
(2) 现将图 $ \textcircled{1} $水平放置在如图 $ \textcircled{2} $所示的数轴上,使得小正方形的顶点 A与数轴上表示1的点重合。若以点 A为圆心,边 DA的长为半径画圆,与数轴交于点 E,求点 E表示的数.
答案
1. (1)5 $\sqrt{5}$ (2)$\sqrt{5}+1$或$-\sqrt{5}+1$
2. 阅读以下解题过程.
$\begin{array}{l} \frac {1}{\sqrt {3} + \sqrt {2}} = \frac {1 × (\sqrt {3} - \sqrt {2})}{(\sqrt {3} + \sqrt {2}) (\sqrt {3} - \sqrt {2})} = \frac {\sqrt {3} - \sqrt {2}}{(\sqrt {3}) ^ {2} - (\sqrt {2}) ^ {2}} = \sqrt {3} - \sqrt {2}, \\ \frac {1}{\sqrt {4} + \sqrt {3}} = \frac {1 × (\sqrt {4} - \sqrt {3})}{(\sqrt {4} + \sqrt {3}) (\sqrt {4} - \sqrt {3})} = \frac {\sqrt {4} - \sqrt {3}}{(\sqrt {4}) ^ {2} - (\sqrt {3}) ^ {2}} = \sqrt {4} - \sqrt {3}. \\ \end{array}$
请回答下列问题:
(1) 观察上面的解答过程,请写出 $ \frac{1}{\sqrt{n+1}+\sqrt{n}}= $
(2) 利用上面的解法,请化简:
$\frac {1}{1 + \sqrt {2}} + \frac {1}{\sqrt {2} + \sqrt {3}} + \frac {1}{\sqrt {3} + \sqrt {4}} + \dots + \frac {1}{\sqrt {9 8} + \sqrt {9 9}} + \frac {1}{\sqrt {9 9} + \sqrt {1 0 0}}.$
$\begin{array}{l} \frac {1}{\sqrt {3} + \sqrt {2}} = \frac {1 × (\sqrt {3} - \sqrt {2})}{(\sqrt {3} + \sqrt {2}) (\sqrt {3} - \sqrt {2})} = \frac {\sqrt {3} - \sqrt {2}}{(\sqrt {3}) ^ {2} - (\sqrt {2}) ^ {2}} = \sqrt {3} - \sqrt {2}, \\ \frac {1}{\sqrt {4} + \sqrt {3}} = \frac {1 × (\sqrt {4} - \sqrt {3})}{(\sqrt {4} + \sqrt {3}) (\sqrt {4} - \sqrt {3})} = \frac {\sqrt {4} - \sqrt {3}}{(\sqrt {4}) ^ {2} - (\sqrt {3}) ^ {2}} = \sqrt {4} - \sqrt {3}. \\ \end{array}$
请回答下列问题:
(1) 观察上面的解答过程,请写出 $ \frac{1}{\sqrt{n+1}+\sqrt{n}}= $
(2) 利用上面的解法,请化简:
$\frac {1}{1 + \sqrt {2}} + \frac {1}{\sqrt {2} + \sqrt {3}} + \frac {1}{\sqrt {3} + \sqrt {4}} + \dots + \frac {1}{\sqrt {9 8} + \sqrt {9 9}} + \frac {1}{\sqrt {9 9} + \sqrt {1 0 0}}.$
答案
2. (1)$\frac{1}{\sqrt{n+1}+\sqrt{n}}=\sqrt{n+1}-\sqrt{n}$ (2)原式$=\frac{\sqrt{2}-1}{(\sqrt{2}+1)(\sqrt{2}-1)}+\frac{\sqrt{3}-\sqrt{2}}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})}+···+\frac{\sqrt{100}-\sqrt{99}}{(\sqrt{100}+\sqrt{99})(\sqrt{100}-\sqrt{99})}=\sqrt{2}-1+\sqrt{3}-\sqrt{2}+···+\sqrt{100}-\sqrt{99}=-1+\sqrt{100}=-1+10=9$.
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