2.列竖式计算,并验算。
7.55 + 5.68 =
10 - 9.57 =
7.55 + 5.68 =
10 - 9.57 =
答案
```
7.55
+ 5.68
-------
13.23
验算:
13.23
5.68
-------
7.55
7.55 + 5.68 = 13.23
10.00
9.57
-------
0.43
验算:
0.43
+ 9.57
-------
10.00
10 - 9.57 = 0.43
```
7.55
+ 5.68
-------
13.23
验算:
13.23
5.68
-------
7.55
7.55 + 5.68 = 13.23
10.00
9.57
-------
0.43
验算:
0.43
+ 9.57
-------
10.00
10 - 9.57 = 0.43
```
3.脱式计算。(能简算的要简算)
38.67 +68.23 +45.8
98.2 -37.18 -10.82
56.23 +31.07 -54.1
32.6 +58.04 +61.96
38.67 +68.23 +45.8
98.2 -37.18 -10.82
56.23 +31.07 -54.1
32.6 +58.04 +61.96
答案
38.67 + 68.23 + 45.8
= 106.9 + 45.8
= 152.7
98.2 - 37.18 - 10.82
= 98.2 - (37.18 + 10.82)
= 98.2 - 48
= 50.2
56.23 + 31.07 - 54.1
= 87.3 - 54.1
= 33.2
32.6 + 58.04 + 61.96
= 32.6 + (58.04 + 61.96)
= 32.6 + 120
= 152.6
= 106.9 + 45.8
= 152.7
98.2 - 37.18 - 10.82
= 98.2 - (37.18 + 10.82)
= 98.2 - 48
= 50.2
56.23 + 31.07 - 54.1
= 87.3 - 54.1
= 33.2
32.6 + 58.04 + 61.96
= 32.6 + (58.04 + 61.96)
= 32.6 + 120
= 152.6
三、解决问题。
1. 下图是瑞瑞抢到的红包截图,请你从中任意选取三个金额,将其改写成分数形式。

1. 下图是瑞瑞抢到的红包截图,请你从中任意选取三个金额,将其改写成分数形式。
答案
选取0.36元、0.47元、0.01元三个金额:
$0.36=\frac{36}{100}$
$0.47=\frac{47}{100}$
$0.01=\frac{1}{100}$
答:选取的三个金额改写成分数形式分别为$\frac{36}{100}$元、$\frac{47}{100}$元、$\frac{1}{100}$元。
(答案不唯一)
$0.36=\frac{36}{100}$
$0.47=\frac{47}{100}$
$0.01=\frac{1}{100}$
答:选取的三个金额改写成分数形式分别为$\frac{36}{100}$元、$\frac{47}{100}$元、$\frac{1}{100}$元。
(答案不唯一)
2.一辆卡车运化肥,第一天上午运了8.8吨,下午比上午多运了2.1吨,第二天比第一天多运了0.5吨,此时已全部运完。这批化肥共有多少吨?
答案
2. 39.9吨
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