2026年通成学典课时作业本八年级数学下册苏科版宿迁专版第111页答案
10. 化简:
(1)$\dfrac{\sqrt{5}}{\sqrt{40}}$;
(2)$\sqrt{\dfrac{18}{a}}(a > 0)$;
(3)$\sqrt{\dfrac{9y}{8x}}(x > 0,y≥ 0)$;
(4)$\dfrac{\sqrt{3a}}{\sqrt{54ab}}(a > 0,b > 0)$;
(5)$x^{2}\sqrt{\dfrac{2}{x}}(x > 0)$;
(6)$\dfrac{m - n}{\sqrt{m - n}}(m > n)$.

答案

10. (1) $\frac{\sqrt{2}}{4}$ (2) $\frac{3\sqrt{2a}}{a}$ (3) $\frac{3\sqrt{2xy}}{4x}$ (4) $\frac{\sqrt{2b}}{6b}$ (5) $x\sqrt{2x}$ (6) $\sqrt{m - n}$

解析

(1)$\dfrac{\sqrt{5}}{\sqrt{40}}=\dfrac{\sqrt{5}}{\sqrt{4×10}}=\dfrac{\sqrt{5}}{2\sqrt{10}}=\dfrac{\sqrt{5}×\sqrt{10}}{2\sqrt{10}×\sqrt{10}}=\dfrac{\sqrt{50}}{20}=\dfrac{5\sqrt{2}}{20}=\dfrac{\sqrt{2}}{4}$;
(2)$\sqrt{\dfrac{18}{a}}=\sqrt{\dfrac{18a}{a^{2}}}=\dfrac{\sqrt{18a}}{a}=\dfrac{3\sqrt{2a}}{a}$;
(3)$\sqrt{\dfrac{9y}{8x}}=\sqrt{\dfrac{9y×2x}{8x×2x}}=\dfrac{\sqrt{18xy}}{4x}=\dfrac{3\sqrt{2xy}}{4x}$;
(4)$\dfrac{\sqrt{3a}}{\sqrt{54ab}}=\sqrt{\dfrac{3a}{54ab}}=\sqrt{\dfrac{1}{18b}}=\sqrt{\dfrac{2b}{18b×2b}}=\dfrac{\sqrt{2b}}{6b}$;
(5)$x^{2}\sqrt{\dfrac{2}{x}}=x^{2}×\dfrac{\sqrt{2x}}{x}=x\sqrt{2x}$;
(6)$\dfrac{m - n}{\sqrt{m - n}}=\dfrac{(m - n)\sqrt{m - n}}{\sqrt{m - n}×\sqrt{m - n}}=\sqrt{m - n}$
11. 计算:
(1)$9\sqrt{\dfrac{1}{48}}÷(-\dfrac{3}{2}\sqrt{2\dfrac{1}{4}})×3\sqrt{1\dfrac{1}{2}}$;
(2)$\dfrac{1}{b}\sqrt{ab^{5}}·(-\dfrac{1}{2}\sqrt{a^{3}b})·2\sqrt{\dfrac{1}{b}}(a > 0,b > 0)$.

答案

11. (1) 原式$=9\sqrt{\frac{1}{48}} ÷ (-\frac{3}{2}\sqrt{\frac{9}{4}}) × 3\sqrt{\frac{3}{2}} = 9 × (-\frac{2}{3}) × 3 × \sqrt{\frac{1}{48} × \frac{4}{9} × \frac{3}{2}} = -18 × \frac{\sqrt{2}}{12} = -\frac{3\sqrt{2}}{2}$ (2) $\frac{1}{b}\sqrt{ab^5} · (-\frac{1}{2}\sqrt{a^3b}) · 2\sqrt{\frac{1}{b}} = (-\frac{1}{b} × \frac{1}{2} × 2) · \sqrt{ab^5 · a^3b · \frac{1}{b}} = -\frac{1}{b}\sqrt{a^4b^5} = -a^2b\sqrt{b}$