2026年学霸的暑假计算暑期大通关五升六年级数学苏教版第52页答案
1. 求比值。(20☆)
9:12=
6:14=
4:16=
6:18=
6:36=
7:49=
8:64=
9:81=
1.6:4.6=
0.4:1.8=
0.6:2.4=
1.6:4.8=
4.2:6.3=
1.8:8.1=
0.13:2.6=
4.6:0.9=
$\frac{1}{3} : \frac{5}{9} =$
$\frac{4}{5} : \frac{12}{25} =$
$\frac{7}{8} : \frac{21}{16} =$
$\frac{6}{13} : \frac{9}{8} =$

答案

1. $\frac{3}{4}$ $\frac{3}{7}$ $\frac{1}{4}$ $\frac{1}{3}$
$\frac{1}{6}$ $\frac{1}{7}$ $\frac{1}{8}$ $\frac{1}{9}$
$\frac{8}{23}$ $\frac{2}{9}$ $\frac{1}{4}$ $\frac{1}{3}$
$\frac{2}{3}$ $\frac{2}{9}$ 0.05 $\frac{46}{9}$
$\frac{3}{5}$ $\frac{5}{3}$ $\frac{2}{3}$ $\frac{16}{39}$
2. 填一填。(12☆)
$\frac{1}{3}:2=(\quad):18$
$(\quad):0.4=2.5:\frac{10}{11}$
$\frac{7}{9}:\frac{7}{10}=\frac{1}{2}:(\quad)$
$3.5:(\quad)=0.7:2$
$15:(\quad)=(\quad):4$
$(\quad):6=\frac{2}{3}:(\quad)$

答案

2. 3 $\frac{11}{10}$ $\frac{9}{20}$ 10
1 60 1 4
(部分答案不唯一)
3. 根据比的基本性质,判断下面每组的两个比能否组成比例,把组成的比例写出来。(12☆)
(1) $1.2:\frac{3}{4}$和$0.8:0.5$
(2) $0.15:\frac{1}{10}$和$1.8:1.2$
(3) $\frac{9}{7}:\frac{1}{5}$和$\frac{9}{14}:\frac{1}{10}$
(
1.2
)×(
0.5
)=(
0.6
) (
$\frac{3}{4}$
)×(
0.8
)=(
0.6
) (
0.15
)×(
1.2
)=(
0.18
)
(
$\frac{1}{10}$
)×(
1.8
)=(
0.18
) (
$\frac{9}{7}$
)×(
$\frac{1}{10}$
)=(
$\frac{9}{70}$
) (
$\frac{1}{5}$
)×(
$\frac{9}{14}$
)=(
$\frac{9}{70}$
)
$1.2:\frac{3}{4}=0.8:0.5$(比例不唯一)
$0.15:\frac{1}{10}=1.8:1.2$(比例不唯一)
$\frac{9}{7}:\frac{1}{5}=\frac{9}{14}:\frac{1}{10}$(比例不唯一)

答案

3. (1)$1.2×0.5=0.6$ $\frac{3}{4}×0.8=0.6$
$1.2:\frac{3}{4}=0.8:0.5$(比例不唯一)
(2)$0.15×1.2=0.18$ $\frac{1}{10}×1.8=0.18$
$0.15:\frac{1}{10}=1.8:1.2$(比例不唯一)
(3)$\frac{9}{7}×\frac{1}{10}=\frac{9}{70}$ $\frac{1}{5}×\frac{9}{14}=\frac{9}{70}$
$\frac{9}{7}:\frac{1}{5}=\frac{9}{14}:\frac{1}{10}$(比例不唯一)
4. 计算下面各题,能简算的要简算。(6☆)
$(\dfrac{7}{19}+\dfrac{2}{5})×19-\dfrac{3}{5}$
$12.5×9.71×0.8$
$0.29÷0.25÷0.4$

答案

4. 14 97.1 2.9