1. 直接写出得数。
$\frac{1}{6}+\frac{5}{6}=$
$\frac{3}{7}-\frac{3}{7}=$
$\frac{1}{8}+\frac{5}{8}=$
$\frac{9}{10}-\frac{3}{10}=$
$1-\frac{4}{7}+\frac{3}{7}=$
$\frac{5}{8}+0=$
$1-\frac{4}{9}=$
$\frac{1}{8}+\frac{1}{4}=$
$\frac{1}{3}-\frac{1}{4}=$
$\frac{1}{2}+\frac{1}{3}=$
$\frac{1}{6}+\frac{5}{6}=$
$\frac{3}{7}-\frac{3}{7}=$
$\frac{1}{8}+\frac{5}{8}=$
$\frac{9}{10}-\frac{3}{10}=$
$1-\frac{4}{7}+\frac{3}{7}=$
$\frac{5}{8}+0=$
$1-\frac{4}{9}=$
$\frac{1}{8}+\frac{1}{4}=$
$\frac{1}{3}-\frac{1}{4}=$
$\frac{1}{2}+\frac{1}{3}=$
答案
1. 1 0 $\frac{3}{4}$ $\frac{3}{5}$ $\frac{6}{7}$ $\frac{5}{8}$ $\frac{5}{9}$ $\frac{3}{8}$ $\frac{1}{12}$ $\frac{5}{6}$
2. 计算下面各题,怎样算简便就怎样算。
$\frac{5}{6}-(\frac{1}{6}+\frac{3}{8})$

$\frac{4}{5}-\frac{3}{10}+\frac{2}{3}$
$1-\frac{17}{18}-\frac{1}{18}$
$\frac{8}{7}+\frac{1}{4}+\frac{1}{4}+\frac{6}{7}$
$\frac{3}{2}-(\frac{3}{4}-\frac{3}{8})$
$\frac{5}{6}-(\frac{1}{6}+\frac{3}{8})$
$\frac{4}{5}-\frac{3}{10}+\frac{2}{3}$
$1-\frac{17}{18}-\frac{1}{18}$
$\frac{8}{7}+\frac{1}{4}+\frac{1}{4}+\frac{6}{7}$
$\frac{3}{2}-(\frac{3}{4}-\frac{3}{8})$
答案
2. $\frac{7}{24}$ $1\frac{2}{3}$ $\frac{7}{6}$ 0 $2\frac{1}{2}$ $\frac{9}{8}$
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