2026年同步解析与测评学考练七年级数学上册人教版第18页答案
2. 计算:
(1)$5.6+4.4+(-8.1)$;
(2)$(-7)+(-4)+(+9)+(-5)$;
(3)$\frac{1}{4}+(-\frac{2}{3})+\frac{5}{6}+(-\frac{1}{4})+(-\frac{1}{3})$;
(4)$5\frac{3}{5}+(-5\frac{2}{3})+4\frac{2}{5}+(-\frac{1}{3})$;
(5)$(-9\frac{5}{12})+15\frac{3}{4}+(-3\frac{1}{4})+(-22.5)+(-15\frac{7}{12})$。

答案

2. 【解】(1)$5.6+4.4+(-8.1)=10-8.1=1.9$;
(2)$(-7)+(-4)+(+9)+(-5)=[(-7)+(-4)+(-5)]+9=[-(7+4+5)]+9=(-16)+9=-7$;
(3)$\frac{1}{4}+(-\frac{2}{3})+\frac{5}{6}+(-\frac{1}{4})+(-\frac{1}{3})=[\frac{1}{4}+(-\frac{1}{4})]+[(-\frac{2}{3})+(-\frac{1}{3})]+\frac{5}{6}=0+(-1)+\frac{5}{6}=-\frac{1}{6}$;
(4)$5\frac{3}{5}+(-5\frac{2}{3})+4\frac{2}{5}+(-\frac{1}{3})=(5\frac{3}{5}+4\frac{2}{5})+[(-5\frac{2}{3})+(-\frac{1}{3})]=10+(-6)=4$;
(5)$(-9\frac{5}{12})+15\frac{3}{4}+(-3\frac{1}{4})+(-22.5)+(-15\frac{7}{12})=[(-9\frac{5}{12})+(-15\frac{7}{12})]+[15\frac{3}{4}+(-3\frac{1}{4})+(-22.5)]=(-25)+[12\frac{1}{2}+(-22.5)]=(-25)+(-10)=-35$.
1. 下列各式运算正确的是 (
D
)

A.$(-3)+(-3)=0$
B.$0+(-3)=3$
C.$(-\frac{1}{4})+(-\frac{1}{5})=-\frac{1}{20}$
D.$(-\frac{1}{3})+(+\frac{1}{3})=0$

答案

1. D
2. 下列变形中,运用加法运算律正确的是
(
B
)

A.$3+(-6)=6+3$
B.$4+(-6)+3=(-6)+4+3$
C.$[5+(-2)]+4=[5+(-4)]+2$
D.$16+(-1)+(+56)=(16+56)+(+1)$

答案

2. B
3. 计算:
(1)$\frac{1}{2}+(-\frac{2}{3})+\frac{4}{5}+(-\frac{1}{2})+(-\frac{1}{3})$;
(2)$43+(-77)+27+(-43)$;
(3)$(+1.25)+(-\frac{1}{2})+(-\frac{3}{4})+(+1\frac{3}{4})$。

答案

3. 【解】(1) 原式$=[\frac{1}{2}+(-\frac{1}{2})]+[(-\frac{2}{3})+(-\frac{1}{3})]+\frac{4}{5}=0+(-1)+\frac{4}{5}=-\frac{1}{5}$;
(2) 原式$=[43+(-43)]+[(-77)+27]=0+(-50)=-50$;
(3) 原式$=[(+1.25)+(+1\frac{3}{4})+(-\frac{3}{4})]+(-\frac{1}{2})=2.25+(-\frac{1}{2})=\frac{7}{4}$.