$\frac{3}{8}+\frac{5}{6}=$
$\frac{1}{2}+\frac{3}{7}=$
$\frac{1}{2}+\frac{3}{7}=$
$\frac{1}{2}-\frac{1}{9}=$
$\frac{5}{6}-\frac{2}{9}=$
$\frac{4}{7}+\frac{2}{3}=$
$\frac{2}{3}+\frac{3}{5}=$
$\frac{3}{10}-\frac{1}{4}=$
$\frac{4}{7}-\frac{2}{5}=$
$\frac{6}{7}-\frac{2}{9}=$
$\frac{1}{2}-\frac{6}{13}=$
$\frac{5}{7}+\frac{1}{5}=$
$\frac{3}{11}+\frac{3}{7}=$
$\frac{2}{3}-\frac{4}{9}=$
$\frac{5}{7}-\frac{3}{11}=$
$\frac{3}{5}+\frac{4}{7}=$
$\frac{5}{6}+\frac{1}{5}=$
$\frac{7}{10}-\frac{3}{5}=$
$\frac{8}{9}-\frac{3}{8}=$
答案
$\frac{29}{24},\frac{13}{14},\frac{7}{18},\frac{11}{18},\frac{26}{21},\frac{19}{15},\frac{1}{20},\frac{6}{35},\frac{40}{63},\frac{1}{26},\frac{32}{35},\frac{54}{77},\frac{2}{9},\frac{34}{77},\frac{41}{35},\frac{31}{30},\frac{1}{10},\frac{37}{72}$
解析
$\frac{3}{8}+\frac{5}{6}=\frac{9}{24}+\frac{20}{24}=\frac{29}{24}$;
$\frac{1}{2}+\frac{3}{7}=\frac{7}{14}+\frac{6}{14}=\frac{13}{14}$;
$\frac{1}{2}-\frac{1}{9}=\frac{9}{18}-\frac{2}{18}=\frac{7}{18}$;
$\frac{5}{6}-\frac{2}{9}=\frac{15}{18}-\frac{4}{18}=\frac{11}{18}$;
$\frac{4}{7}+\frac{2}{3}=\frac{12}{21}+\frac{14}{21}=\frac{26}{21}$;
$\frac{2}{3}+\frac{3}{5}=\frac{10}{15}+\frac{9}{15}=\frac{19}{15}$;
$\frac{3}{10}-\frac{1}{4}=\frac{6}{20}-\frac{5}{20}=\frac{1}{20}$;
$\frac{4}{7}-\frac{2}{5}=\frac{20}{35}-\frac{14}{35}=\frac{6}{35}$;
$\frac{6}{7}-\frac{2}{9}=\frac{54}{63}-\frac{14}{63}=\frac{40}{63}$;
$\frac{1}{2}-\frac{6}{13}=\frac{13}{26}-\frac{12}{26}=\frac{1}{26}$;
$\frac{5}{7}+\frac{1}{5}=\frac{25}{35}+\frac{7}{35}=\frac{32}{35}$;
$\frac{3}{11}+\frac{3}{7}=\frac{21}{77}+\frac{33}{77}=\frac{54}{77}$;
$\frac{2}{3}-\frac{4}{9}=\frac{6}{9}-\frac{4}{9}=\frac{2}{9}$;
$\frac{5}{7}-\frac{3}{11}=\frac{55}{77}-\frac{21}{77}=\frac{34}{77}$;
$\frac{3}{5}+\frac{4}{7}=\frac{21}{35}+\frac{20}{35}=\frac{41}{35}$;
$\frac{5}{6}+\frac{1}{5}=\frac{25}{30}+\frac{6}{30}=\frac{31}{30}$;
$\frac{7}{10}-\frac{3}{5}=\frac{7}{10}-\frac{6}{10}=\frac{1}{10}$;
$\frac{8}{9}-\frac{3}{8}=\frac{64}{72}-\frac{27}{72}=\frac{37}{72}$
$\frac{1}{2}+\frac{3}{7}=\frac{7}{14}+\frac{6}{14}=\frac{13}{14}$;
$\frac{1}{2}-\frac{1}{9}=\frac{9}{18}-\frac{2}{18}=\frac{7}{18}$;
$\frac{5}{6}-\frac{2}{9}=\frac{15}{18}-\frac{4}{18}=\frac{11}{18}$;
$\frac{4}{7}+\frac{2}{3}=\frac{12}{21}+\frac{14}{21}=\frac{26}{21}$;
$\frac{2}{3}+\frac{3}{5}=\frac{10}{15}+\frac{9}{15}=\frac{19}{15}$;
$\frac{3}{10}-\frac{1}{4}=\frac{6}{20}-\frac{5}{20}=\frac{1}{20}$;
$\frac{4}{7}-\frac{2}{5}=\frac{20}{35}-\frac{14}{35}=\frac{6}{35}$;
$\frac{6}{7}-\frac{2}{9}=\frac{54}{63}-\frac{14}{63}=\frac{40}{63}$;
$\frac{1}{2}-\frac{6}{13}=\frac{13}{26}-\frac{12}{26}=\frac{1}{26}$;
$\frac{5}{7}+\frac{1}{5}=\frac{25}{35}+\frac{7}{35}=\frac{32}{35}$;
$\frac{3}{11}+\frac{3}{7}=\frac{21}{77}+\frac{33}{77}=\frac{54}{77}$;
$\frac{2}{3}-\frac{4}{9}=\frac{6}{9}-\frac{4}{9}=\frac{2}{9}$;
$\frac{5}{7}-\frac{3}{11}=\frac{55}{77}-\frac{21}{77}=\frac{34}{77}$;
$\frac{3}{5}+\frac{4}{7}=\frac{21}{35}+\frac{20}{35}=\frac{41}{35}$;
$\frac{5}{6}+\frac{1}{5}=\frac{25}{30}+\frac{6}{30}=\frac{31}{30}$;
$\frac{7}{10}-\frac{3}{5}=\frac{7}{10}-\frac{6}{10}=\frac{1}{10}$;
$\frac{8}{9}-\frac{3}{8}=\frac{64}{72}-\frac{27}{72}=\frac{37}{72}$
解方程
$x+\frac{1}{5}=\frac{4}{5}$
$x-\frac{7}{12}=\frac{1}{3}$
$\frac{4}{9}+x=1$
$x+\frac{1}{5}=\frac{4}{5}$
$x-\frac{7}{12}=\frac{1}{3}$
$\frac{4}{9}+x=1$
答案
【解析】:
1. $x+\frac{1}{5}=\frac{4}{5}$
解:$x=\frac{4}{5}-\frac{1}{5}$
$x=\frac{3}{5}$
2. $x-\frac{7}{12}=\frac{1}{3}$
解:$x=\frac{1}{3}+\frac{7}{12}$
$x=\frac{4}{12}+\frac{7}{12}$
$x=\frac{11}{12}$
3. $\frac{4}{9}+x=1$
解:$x=1-\frac{4}{9}$
$x=\frac{9}{9}-\frac{4}{9}$
$x=\frac{5}{9}$
【答案】:$x=\frac{3}{5}$,$x=\frac{11}{12}$,$x=\frac{5}{9}$
1. $x+\frac{1}{5}=\frac{4}{5}$
解:$x=\frac{4}{5}-\frac{1}{5}$
$x=\frac{3}{5}$
2. $x-\frac{7}{12}=\frac{1}{3}$
解:$x=\frac{1}{3}+\frac{7}{12}$
$x=\frac{4}{12}+\frac{7}{12}$
$x=\frac{11}{12}$
3. $\frac{4}{9}+x=1$
解:$x=1-\frac{4}{9}$
$x=\frac{9}{9}-\frac{4}{9}$
$x=\frac{5}{9}$
【答案】:$x=\frac{3}{5}$,$x=\frac{11}{12}$,$x=\frac{5}{9}$
解析
1. $x+\frac{1}{5}=\frac{4}{5}$
解:$x=\frac{4}{5}-\frac{1}{5}$
$x=\frac{3}{5}$
2. $x-\frac{7}{12}=\frac{1}{3}$
解:$x=\frac{1}{3}+\frac{7}{12}$
$x=\frac{4}{12}+\frac{7}{12}$
$x=\frac{11}{12}$
3. $\frac{4}{9}+x=1$
解:$x=1-\frac{4}{9}$
$x=\frac{9}{9}-\frac{4}{9}$
$x=\frac{5}{9}$
解:$x=\frac{4}{5}-\frac{1}{5}$
$x=\frac{3}{5}$
2. $x-\frac{7}{12}=\frac{1}{3}$
解:$x=\frac{1}{3}+\frac{7}{12}$
$x=\frac{4}{12}+\frac{7}{12}$
$x=\frac{11}{12}$
3. $\frac{4}{9}+x=1$
解:$x=1-\frac{4}{9}$
$x=\frac{9}{9}-\frac{4}{9}$
$x=\frac{5}{9}$
连一连
$\frac{1}{3}+\frac{1}{5}$
$\frac{1}{10}-\frac{1}{20}$
$\frac{5}{8}-\frac{1}{9}$
$\frac{3}{4}+\frac{1}{5}$
$\frac{2}{3}-\frac{3}{5}$
$\frac{1}{4}+\frac{5}{6}$

接近0
接近1
接近$\frac{1}{2}$
$\frac{1}{3}+\frac{1}{5}$
$\frac{1}{10}-\frac{1}{20}$
$\frac{5}{8}-\frac{1}{9}$
$\frac{3}{4}+\frac{1}{5}$
$\frac{2}{3}-\frac{3}{5}$
$\frac{1}{4}+\frac{5}{6}$
接近0
接近1
接近$\frac{1}{2}$
答案
接近0连$\frac{1}{10}-\frac{1}{20}$、$\frac{2}{3}-\frac{3}{5}$;接近1连$\frac{3}{4}+\frac{1}{5}$、$\frac{1}{4}+\frac{5}{6}$;接近$\frac{1}{2}$连$\frac{1}{3}+\frac{1}{5}$、$\frac{5}{8}-\frac{1}{9}$
解析
1. $\frac{1}{3}+\frac{1}{5}=\frac{5}{15}+\frac{3}{15}=\frac{8}{15}\approx0.53$,接近$\frac{1}{2}$
2. $\frac{1}{10}-\frac{1}{20}=\frac{2}{20}-\frac{1}{20}=\frac{1}{20}=0.05$,接近0
3. $\frac{5}{8}-\frac{1}{9}=\frac{45}{72}-\frac{8}{72}=\frac{37}{72}\approx0.51$,接近$\frac{1}{2}$
4. $\frac{3}{4}+\frac{1}{5}=\frac{15}{20}+\frac{4}{20}=\frac{19}{20}=0.95$,接近1
5. $\frac{2}{3}-\frac{3}{5}=\frac{10}{15}-\frac{9}{15}=\frac{1}{15}\approx0.07$,接近0
6. $\frac{1}{4}+\frac{5}{6}=\frac{3}{12}+\frac{10}{12}=\frac{13}{12}\approx1.08$,接近1
接近0:$\frac{1}{10}-\frac{1}{20}$,$\frac{2}{3}-\frac{3}{5}$
接近1:$\frac{3}{4}+\frac{1}{5}$,$\frac{1}{4}+\frac{5}{6}$
接近$\frac{1}{2}$:$\frac{1}{3}+\frac{1}{5}$,$\frac{5}{8}-\frac{1}{9}$
2. $\frac{1}{10}-\frac{1}{20}=\frac{2}{20}-\frac{1}{20}=\frac{1}{20}=0.05$,接近0
3. $\frac{5}{8}-\frac{1}{9}=\frac{45}{72}-\frac{8}{72}=\frac{37}{72}\approx0.51$,接近$\frac{1}{2}$
4. $\frac{3}{4}+\frac{1}{5}=\frac{15}{20}+\frac{4}{20}=\frac{19}{20}=0.95$,接近1
5. $\frac{2}{3}-\frac{3}{5}=\frac{10}{15}-\frac{9}{15}=\frac{1}{15}\approx0.07$,接近0
6. $\frac{1}{4}+\frac{5}{6}=\frac{3}{12}+\frac{10}{12}=\frac{13}{12}\approx1.08$,接近1
接近0:$\frac{1}{10}-\frac{1}{20}$,$\frac{2}{3}-\frac{3}{5}$
接近1:$\frac{3}{4}+\frac{1}{5}$,$\frac{1}{4}+\frac{5}{6}$
接近$\frac{1}{2}$:$\frac{1}{3}+\frac{1}{5}$,$\frac{5}{8}-\frac{1}{9}$
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