$4x + 0.5 = 6.5$ $x\div4 - 1.07 = 0.93$ $6x - 8.5\times4 = 20$
$2.3x - 12.5 = 19.7$ $(x - 5)\div4 = 3.5$ $37.7x + 17.8x = 33.3$
$1.3x + 0.2x = 45$ $(4.5 + x)\times2 = 13$ $4.2x + 2.5x = 134$
$x - 0.9x = 81.9$ $2x - 8.15 = 18.17$ $12x\div5 = 4.8$
$7x + 10\times0.53 = 7.4$ $0.5x + 3.4x = 8.58$ $0.5x - 5 = 21$
$0.16x\div4.8 = 2.5$ $5x - 2 + 1.8 = 3.6$ $8x + 2.5\times2 = 37$
$x\div1.2 + 2.5 = 4.7$ $3.75x - 2.25x = 3$ $9(x + 1.1) = 18.9$
$3(x - 12) = 2.1$ $5x - 21.6 = 3.4$ $18 - 9 + 5x = 13.5$
$x - \frac{1}{3} = \frac{4}{5} - \frac{1}{2}$ $\frac{3}{8} + \frac{4}{7} - x = \frac{7}{8}$ $x - (\frac{7}{9} - \frac{1}{5}) = \frac{6}{5}$
$x + \frac{1}{10} - \frac{2}{5} = \frac{3}{4}$ $\frac{11}{15} - x + \frac{3}{5} = \frac{1}{2}$ $x + \frac{3}{4} - \frac{1}{3} = \frac{4}{3}$
$x + (\frac{11}{20} - \frac{1}{4}) = \frac{7}{10}$ $x - \frac{1}{2} + \frac{3}{14} = \frac{6}{7}$ $x - \frac{2}{5} - \frac{1}{3} = \frac{5}{9}$
$x - \frac{5}{6} + \frac{1}{3} = \frac{7}{8}$ $x - (\frac{2}{11} + \frac{1}{5}) = \frac{4}{5}$ $\frac{2}{7} + x - \frac{4}{9} = \frac{2}{3}$
$2.3x - 12.5 = 19.7$ $(x - 5)\div4 = 3.5$ $37.7x + 17.8x = 33.3$
$1.3x + 0.2x = 45$ $(4.5 + x)\times2 = 13$ $4.2x + 2.5x = 134$
$x - 0.9x = 81.9$ $2x - 8.15 = 18.17$ $12x\div5 = 4.8$
$7x + 10\times0.53 = 7.4$ $0.5x + 3.4x = 8.58$ $0.5x - 5 = 21$
$0.16x\div4.8 = 2.5$ $5x - 2 + 1.8 = 3.6$ $8x + 2.5\times2 = 37$
$x\div1.2 + 2.5 = 4.7$ $3.75x - 2.25x = 3$ $9(x + 1.1) = 18.9$
$3(x - 12) = 2.1$ $5x - 21.6 = 3.4$ $18 - 9 + 5x = 13.5$
$x - \frac{1}{3} = \frac{4}{5} - \frac{1}{2}$ $\frac{3}{8} + \frac{4}{7} - x = \frac{7}{8}$ $x - (\frac{7}{9} - \frac{1}{5}) = \frac{6}{5}$
$x + \frac{1}{10} - \frac{2}{5} = \frac{3}{4}$ $\frac{11}{15} - x + \frac{3}{5} = \frac{1}{2}$ $x + \frac{3}{4} - \frac{1}{3} = \frac{4}{3}$
$x + (\frac{11}{20} - \frac{1}{4}) = \frac{7}{10}$ $x - \frac{1}{2} + \frac{3}{14} = \frac{6}{7}$ $x - \frac{2}{5} - \frac{1}{3} = \frac{5}{9}$
$x - \frac{5}{6} + \frac{1}{3} = \frac{7}{8}$ $x - (\frac{2}{11} + \frac{1}{5}) = \frac{4}{5}$ $\frac{2}{7} + x - \frac{4}{9} = \frac{2}{3}$
答案
登录