2025年通城学典计算能手五年级数学下册苏教版江苏专版第119页答案
$\frac{1}{8} + \frac{1}{2} =$ $\frac{11}{23} - \frac{7}{46} =$ $\frac{11}{15} + \frac{7}{30} =$
$\frac{9}{10} - \frac{3}{4} =$ $\frac{2}{17} + \frac{3}{34} =$ $\frac{8}{9} - \frac{3}{8} =$
$\frac{5}{9} + \frac{1}{3} =$ $\frac{7}{10} - \frac{2}{5} =$ $\frac{3}{10} + \frac{2}{5} =$
$\frac{5}{6} - \frac{2}{3} =$ $\frac{2}{21} + \frac{4}{7} =$ $\frac{19}{30} - \frac{4}{15} =$
$\frac{1}{4} + \frac{1}{6} =$ $\frac{11}{12} - \frac{2}{3} =$ $\frac{2}{11} + \frac{1}{2} =$
$\frac{9}{16} - \frac{3}{8} =$ $\frac{5}{26} + \frac{3}{13} =$ $\frac{7}{9} - \frac{3}{8} =$
$\frac{4}{21} + \frac{2}{7} =$ $\frac{3}{7} - \frac{1}{8} =$ $\frac{2}{9} + \frac{3}{5} =$
$\frac{4}{5} - \frac{1}{2} =$ $\frac{2}{3} + \frac{5}{6} =$ $\frac{12}{13} - \frac{3}{5} =$
$\frac{3}{4} + \frac{2}{5} =$ $\frac{14}{33} - \frac{3}{11} =$ $\frac{3}{7} + \frac{1}{4} =$
$\frac{3}{16} - \frac{5}{48} =$ $\frac{7}{12} + \frac{2}{3} =$ $\frac{7}{40} + \frac{9}{20} =$
$\frac{7}{12} + \frac{1}{24} =$ $\frac{9}{13} - \frac{5}{39} =$ $\frac{14}{45} - \frac{1}{15} =$
$\frac{3}{4} - \frac{5}{9} =$ $\frac{3}{8} + \frac{1}{12} =$ $\frac{22}{23} - \frac{17}{46} =$
$\frac{1}{3} + \frac{1}{8} =$ $\frac{23}{36} - \frac{5}{18} =$ $\frac{3}{16} + \frac{5}{12} =$
$\frac{1}{5} - \frac{1}{7} =$ $\frac{4}{11} + \frac{5}{22} =$ $\frac{19}{21} - \frac{2}{7} =$
$\frac{1}{9} + \frac{3}{10} =$ $\frac{15}{17} - \frac{11}{51} =$ $\frac{1}{10} + \frac{4}{5} =$
$\frac{6}{7} - \frac{2}{3} =$ $\frac{5}{16} + \frac{3}{8} =$ $\frac{11}{12} - \frac{5}{16} =$

答案

$\frac{3}{4} + \frac{5}{6} - \frac{5}{12}$ $\frac{6}{7} - (\frac{3}{14} + \frac{3}{7})$ $\frac{3}{10} + \frac{5}{9} + \frac{7}{10} - \frac{5}{9}$
$\frac{5}{6} - (\frac{2}{3} - \frac{4}{9})$ $\frac{7}{9} - \frac{2}{3} + \frac{1}{5}$ $\frac{29}{17} - (\frac{3}{17} + \frac{2}{5}) - \frac{3}{5}$
$\frac{5}{12} + (\frac{3}{4} - \frac{1}{8})$ $\frac{7}{9} + \frac{2}{3} - \frac{4}{5}$ $\frac{11}{7} + \frac{11}{12} - \frac{4}{7} - \frac{5}{12}$
$\frac{11}{12} - \frac{2}{5} - \frac{3}{10}$ $\frac{14}{15} - (\frac{7}{6} - \frac{1}{2})$ $\frac{9}{4} - \frac{5}{16} - \frac{11}{16} + \frac{3}{4}$
$\frac{13}{12} - (\frac{5}{6} - \frac{1}{3})$ $\frac{4}{5} - \frac{3}{10} + \frac{8}{15}$ $\frac{17}{20} + \frac{5}{7} - \frac{7}{20} + \frac{2}{7}$
$\frac{11}{12} - (\frac{3}{8} + \frac{1}{12})$ $\frac{9}{10} + (\frac{3}{7} - \frac{1}{10})$ $\frac{17}{18} - \frac{2}{9} - (\frac{3}{9} - \frac{1}{18})$

答案