1. 口算。
0.9×0.3=
0.45×0.1=
100×0.03=
0.25×4=
0.5×0.5=
0.201×1=
0.125×8=
0.6÷10=
0.9×0.3=
0.45×0.1=
100×0.03=
0.25×4=
0.5×0.5=
0.201×1=
0.125×8=
0.6÷10=
答案
0.9×0.3=0.27
0.45×0.1=0.045
100×0.03=3
0.25×4=1
0.5×0.5=0.25
0.201×1=0.201
0.125×8=1
0.6÷10=0.06
0.45×0.1=0.045
100×0.03=3
0.25×4=1
0.5×0.5=0.25
0.201×1=0.201
0.125×8=1
0.6÷10=0.06
2. 完成下面的表格。
| 乘数 | 23 | 2.3 | 2.3 | 0.23 | 23 | |
| ---- | ---- | ---- | ---- | ---- | ---- | ---- |
| 乘数 | 72 | 72 |
| 7.2 | 0.72 | |
| 积 | 1656 | | | | | 16.56 |
| 乘数 | 23 | 2.3 | 2.3 | 0.23 | 23 | |
| ---- | ---- | ---- | ---- | ---- | ---- | ---- |
| 乘数 | 72 | 72 |
| 积 | 1656 | | | | | 16.56 |
答案
165.6
16.56
1.656
16.56
2.3
7.2
16.56
1.656
16.56
2.3
7.2
3. 计算。
$70.5×4.5$
$0.14×3.27$
$0.45×8.06$
$0.25×0.91×4$
$0.98×6.4+0.98×3.6$
$1.25×0.4×0.25×8$
$10-0.45-0.55$
$70.5×4.5$
$0.14×3.27$
$0.45×8.06$
$0.25×0.91×4$
$0.98×6.4+0.98×3.6$
$1.25×0.4×0.25×8$
$10-0.45-0.55$
答案
70.5×4.5
=70.5×4 +70.5×0.5
=282 +35.25
=317.25
0.14×3.27
=0.14×3 +0.14×0.27
=0.42 +0.0378
=0.4578
0.45×8.06
=0.45×8 +0.45×0.06
=3.6 +0.027
=3.627
0.25×0.91×4
=0.25×4×0.91
=1×0.91
=0.91
0.98×6.4+0.98×3.6
=0.98×(6.4+3.6)
=0.98×10
=9.8
1.25×0.4×0.25×8
=(1.25×8)×(0.4×0.25)
=10×0.1
=1
10-0.45-0.55
=10-(0.45+0.55)
=10-1
=9
=70.5×4 +70.5×0.5
=282 +35.25
=317.25
0.14×3.27
=0.14×3 +0.14×0.27
=0.42 +0.0378
=0.4578
0.45×8.06
=0.45×8 +0.45×0.06
=3.6 +0.027
=3.627
0.25×0.91×4
=0.25×4×0.91
=1×0.91
=0.91
0.98×6.4+0.98×3.6
=0.98×(6.4+3.6)
=0.98×10
=9.8
1.25×0.4×0.25×8
=(1.25×8)×(0.4×0.25)
=10×0.1
=1
10-0.45-0.55
=10-(0.45+0.55)
=10-1
=9
4. 李阿姨买了四种蔬菜,总价分别如下表。
(1)黄瓜和茄子的总价之和不到15元,黄瓜和茄子的总价可能分别是多少元?

(2)买另外两种蔬菜,付了50元,找回25元,对吗?
(1)黄瓜和茄子的总价之和不到15元,黄瓜和茄子的总价可能分别是多少元?
(2)买另外两种蔬菜,付了50元,找回25元,对吗?
答案
(1)
7.02 + 7.89 = 14.91(元)
14.91元<15元,符合条件。
答:黄瓜和茄子的总价可能分别是7.02元和7.89元。
(2)
12.73 + 12.27 = 25(元)
50 - 25 = 25(元)
答:对。
7.02 + 7.89 = 14.91(元)
14.91元<15元,符合条件。
答:黄瓜和茄子的总价可能分别是7.02元和7.89元。
(2)
12.73 + 12.27 = 25(元)
50 - 25 = 25(元)
答:对。
登录