1. 计算:
(1)$\sqrt{4}\times\sqrt{9}=$__________,$\sqrt{4\times9}=$__________;
(2)$\sqrt{49}\times\sqrt{16}=$__________,$\sqrt{49\times16}=$__________;
(3)$\sqrt{\frac{4}{9}\times\frac{16}{25}}=$__________,$\sqrt{\frac{4}{9}}\times\sqrt{\frac{16}{25}}=$__________.
(1)$\sqrt{4}\times\sqrt{9}=$__________,$\sqrt{4\times9}=$__________;
(2)$\sqrt{49}\times\sqrt{16}=$__________,$\sqrt{49\times16}=$__________;
(3)$\sqrt{\frac{4}{9}\times\frac{16}{25}}=$__________,$\sqrt{\frac{4}{9}}\times\sqrt{\frac{16}{25}}=$__________.
答案
2. 计算:
(1)$\sqrt{27}\times\sqrt{3}$; (2)$\sqrt{15}\times\sqrt{\frac{5}{3}}$;
(3)$\sqrt{63}\times\sqrt{14}\times\sqrt{2}$; (4)$\sqrt{2a}\cdot\sqrt{\frac{a}{2}}\cdot\sqrt{a^{2}}$($a\geq0$).
(1)$\sqrt{27}\times\sqrt{3}$; (2)$\sqrt{15}\times\sqrt{\frac{5}{3}}$;
(3)$\sqrt{63}\times\sqrt{14}\times\sqrt{2}$; (4)$\sqrt{2a}\cdot\sqrt{\frac{a}{2}}\cdot\sqrt{a^{2}}$($a\geq0$).
答案
3. 化简:
(1)$\sqrt{18}$; (2)$\sqrt{27}$;
(3)$\sqrt{32}$; (4)$\sqrt{72}$;
(5)$\sqrt{12a^{2}b^{3}}(a\geq0,b\geq0)$; (6)$\sqrt{13^{2}-12^{2}}$.
(1)$\sqrt{18}$; (2)$\sqrt{27}$;
(3)$\sqrt{32}$; (4)$\sqrt{72}$;
(5)$\sqrt{12a^{2}b^{3}}(a\geq0,b\geq0)$; (6)$\sqrt{13^{2}-12^{2}}$.
答案
登录