6.怎样算简便就怎样算。
$\frac{7}{24} × \frac{3}{4} + \frac{7}{24} ÷ 4$
$0.5 × ( \frac{3}{5} + \frac{6}{25} )$
$\frac{8}{17} ÷ 23 + \frac{1}{23} × \frac{9}{17}$
$\frac{3}{5} ÷ \frac{6}{7} + \frac{8}{9} + \frac{3}{10} + \frac{1}{9}$
$( \frac{2}{3} + \frac{5}{8} ) ÷ \frac{1}{24}$
$( \frac{4}{5} + \frac{2}{7} + \frac{6}{5} ) ÷ \frac{2}{7}$
$\frac{7}{24} × \frac{3}{4} + \frac{7}{24} ÷ 4$
$0.5 × ( \frac{3}{5} + \frac{6}{25} )$
$\frac{8}{17} ÷ 23 + \frac{1}{23} × \frac{9}{17}$
$\frac{3}{5} ÷ \frac{6}{7} + \frac{8}{9} + \frac{3}{10} + \frac{1}{9}$
$( \frac{2}{3} + \frac{5}{8} ) ÷ \frac{1}{24}$
$( \frac{4}{5} + \frac{2}{7} + \frac{6}{5} ) ÷ \frac{2}{7}$
答案
$\frac{7}{24} × \frac{3}{4} + \frac{7}{24} ÷ 4$
$=\frac{7}{24}×\frac{3}{4} + \frac{7}{24}×\frac{1}{4}$
$=\frac{7}{24}×(\frac{3}{4}+\frac{1}{4})$
$=\frac{7}{24}×1$
$=\frac{7}{24}$
$0.5 × ( \frac{3}{5} + \frac{6}{25} )$
$=\frac{1}{2}×\frac{3}{5} + \frac{1}{2}×\frac{6}{25}$
$=\frac{3}{10} + \frac{3}{25}$
$=\frac{15}{50} + \frac{6}{50}$
$=\frac{21}{50}$
$\frac{8}{17} ÷ 23 + \frac{1}{23} × \frac{9}{17}$
$=\frac{8}{17}×\frac{1}{23} + \frac{1}{23}×\frac{9}{17}$
$=\frac{1}{23}×(\frac{8}{17}+\frac{9}{17})$
$=\frac{1}{23}×1$
$=\frac{1}{23}$
$\frac{3}{5} ÷ \frac{6}{7} + \frac{8}{9} + \frac{3}{10} + \frac{1}{9}$
$=\frac{7}{10} + \frac{3}{10} + (\frac{8}{9}+\frac{1}{9})$
$=1 + 1$
$=2$
$( \frac{2}{3} + \frac{5}{8} ) ÷ \frac{1}{24}$
$=(\frac{2}{3}+\frac{5}{8})×24$
$=\frac{2}{3}×24 + \frac{5}{8}×24$
$=16 + 15$
$=31$
$( \frac{4}{5} + \frac{2}{7} + \frac{6}{5} ) ÷ \frac{2}{7}$
$=(\frac{4}{5}+\frac{6}{5}+\frac{2}{7})×\frac{7}{2}$
$=(2+\frac{2}{7})×\frac{7}{2}$
$=2×\frac{7}{2} + \frac{2}{7}×\frac{7}{2}$
$=7 + 1$
$=8$
$=\frac{7}{24}×\frac{3}{4} + \frac{7}{24}×\frac{1}{4}$
$=\frac{7}{24}×(\frac{3}{4}+\frac{1}{4})$
$=\frac{7}{24}×1$
$=\frac{7}{24}$
$0.5 × ( \frac{3}{5} + \frac{6}{25} )$
$=\frac{1}{2}×\frac{3}{5} + \frac{1}{2}×\frac{6}{25}$
$=\frac{3}{10} + \frac{3}{25}$
$=\frac{15}{50} + \frac{6}{50}$
$=\frac{21}{50}$
$\frac{8}{17} ÷ 23 + \frac{1}{23} × \frac{9}{17}$
$=\frac{8}{17}×\frac{1}{23} + \frac{1}{23}×\frac{9}{17}$
$=\frac{1}{23}×(\frac{8}{17}+\frac{9}{17})$
$=\frac{1}{23}×1$
$=\frac{1}{23}$
$\frac{3}{5} ÷ \frac{6}{7} + \frac{8}{9} + \frac{3}{10} + \frac{1}{9}$
$=\frac{7}{10} + \frac{3}{10} + (\frac{8}{9}+\frac{1}{9})$
$=1 + 1$
$=2$
$( \frac{2}{3} + \frac{5}{8} ) ÷ \frac{1}{24}$
$=(\frac{2}{3}+\frac{5}{8})×24$
$=\frac{2}{3}×24 + \frac{5}{8}×24$
$=16 + 15$
$=31$
$( \frac{4}{5} + \frac{2}{7} + \frac{6}{5} ) ÷ \frac{2}{7}$
$=(\frac{4}{5}+\frac{6}{5}+\frac{2}{7})×\frac{7}{2}$
$=(2+\frac{2}{7})×\frac{7}{2}$
$=2×\frac{7}{2} + \frac{2}{7}×\frac{7}{2}$
$=7 + 1$
$=8$
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