3. 甲、乙两堆煤共有 35 吨,如果各用掉$\dfrac{1}{5}$,甲堆煤还剩下 12 吨。乙堆煤还剩下多少吨?
答案
16吨
解析
甲堆煤原有:$12÷(1 - \frac{1}{5}) = 12÷\frac{4}{5} = 15$(吨)
乙堆煤原有:$35 - 15 = 20$(吨)
乙堆煤剩下:$20×(1 - \frac{1}{5}) = 20×\frac{4}{5} = 16$(吨)
16吨
乙堆煤原有:$35 - 15 = 20$(吨)
乙堆煤剩下:$20×(1 - \frac{1}{5}) = 20×\frac{4}{5} = 16$(吨)
16吨
1. 用你喜欢的方法计算下面各题。
$(12+\dfrac{5}{6})×6$
$\dfrac{4}{5}×\dfrac{1}{4}-\dfrac{1}{4}×\dfrac{4}{5}$
$(30×\dfrac{1}{4}-\dfrac{5}{2})÷\dfrac{5}{6}$
$(12+\dfrac{5}{6})×6$
$\dfrac{4}{5}×\dfrac{1}{4}-\dfrac{1}{4}×\dfrac{4}{5}$
$(30×\dfrac{1}{4}-\dfrac{5}{2})÷\dfrac{5}{6}$
答案
77 0 6
解析
$(12+\dfrac{5}{6})×6=12×6+\dfrac{5}{6}×6=72+5=77$
$\dfrac{4}{5}×\dfrac{1}{4}-\dfrac{1}{4}×\dfrac{4}{5}=\dfrac{1}{5}-\dfrac{1}{5}=0$
$(30×\dfrac{1}{4}-\dfrac{5}{2})÷\dfrac{5}{6}=(\dfrac{15}{2}-\dfrac{5}{2})×\dfrac{6}{5}=5×\dfrac{6}{5}=6$
$480×(1-\dfrac{2}{3})=480×\dfrac{1}{3}=160$(页)
$\dfrac{4}{5}×\dfrac{1}{4}-\dfrac{1}{4}×\dfrac{4}{5}=\dfrac{1}{5}-\dfrac{1}{5}=0$
$(30×\dfrac{1}{4}-\dfrac{5}{2})÷\dfrac{5}{6}=(\dfrac{15}{2}-\dfrac{5}{2})×\dfrac{6}{5}=5×\dfrac{6}{5}=6$
$480×(1-\dfrac{2}{3})=480×\dfrac{1}{3}=160$(页)
2.
答案
2.160页
3. 20 千克奶糖,卖出$\dfrac{1}{4}$后又卖出$\dfrac{1}{4}$千克,还剩多少千克?
答案
$14\frac{3}{4}$千克
解析
20 - 20×$\dfrac{1}{4}$ - $\dfrac{1}{4}$
= 20 - 5 - $\dfrac{1}{4}$
= 15 - $\dfrac{1}{4}$
= $14\dfrac{3}{4}$(千克)
答:还剩$14\dfrac{3}{4}$千克。
= 20 - 5 - $\dfrac{1}{4}$
= 15 - $\dfrac{1}{4}$
= $14\dfrac{3}{4}$(千克)
答:还剩$14\dfrac{3}{4}$千克。
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