(1) 图略(在数射线上找到
(2) 比较下列分数的大小。
$\frac{2}{5}$○$\frac{2}{3}$
$\frac{5}{6}$○$\frac{3}{6}$
1○$\frac{8}{8}$
$\frac{4}{8}$○$\frac{3}{6}$
$\frac{4}{8}$○$\frac{4}{5}$
$\frac{3}{6}$○$\frac{4}{5}$
$\frac{2}{3}$、$\frac{4}{8}$(即$\frac{1}{2}$)、$\frac{4}{5}$和$\frac{5}{6}$
对应的位置标出即可)。(2) 比较下列分数的大小。
$\frac{2}{5}$○$\frac{2}{3}$
<
$\frac{5}{6}$○$\frac{3}{6}$
>
1○$\frac{8}{8}$
=
$\frac{4}{8}$○$\frac{3}{6}$
=
$\frac{4}{8}$○$\frac{4}{5}$
<
$\frac{3}{6}$○$\frac{4}{5}$
<
答案
(1) 图略(在数射线上找到$\frac{2}{3}$、$\frac{4}{8}$(即$\frac{1}{2}$)、$\frac{4}{5}$和$\frac{5}{6}$对应的位置标出即可)。
(2)
$\frac{2}{5} \lt \frac{2}{3}$;
$\frac{5}{6} \gt \frac{3}{6}$;
$1 = \frac{8}{8}$;
$\frac{4}{8}=\frac{1}{2}$,$\frac{3}{6} =\frac{1}{2}$,所以$\frac{4}{8}=\frac{3}{6}$;
$\frac{4}{8} \lt \frac{4}{5}$;
$\frac{3}{6}=\frac{1}{2}$,$\frac{4}{5} \gt \frac{1}{2}$,所以$\frac{3}{6} \lt \frac{4}{5}$。
(2)
$\frac{2}{5} \lt \frac{2}{3}$;
$\frac{5}{6} \gt \frac{3}{6}$;
$1 = \frac{8}{8}$;
$\frac{4}{8}=\frac{1}{2}$,$\frac{3}{6} =\frac{1}{2}$,所以$\frac{4}{8}=\frac{3}{6}$;
$\frac{4}{8} \lt \frac{4}{5}$;
$\frac{3}{6}=\frac{1}{2}$,$\frac{4}{5} \gt \frac{1}{2}$,所以$\frac{3}{6} \lt \frac{4}{5}$。
(1)$\frac{2}{16}+\frac{7}{16}=$
(2)$\frac{10}{20}-\frac{6}{20}=$
(3)$\frac{3}{19}+\frac{8}{19}+\frac{5}{19}=$
(4)$\frac{12}{18}-\frac{7}{18}-\frac{3}{18}=$
(5)$\frac{8}{17}+\frac{9}{17}-\frac{8}{13}=$
(6)$\frac{11}{15}-\frac{13}{18}+\frac{4}{15}=$
$\frac{9}{16}$
(2)$\frac{10}{20}-\frac{6}{20}=$
$\frac{1}{5}$
(3)$\frac{3}{19}+\frac{8}{19}+\frac{5}{19}=$
$\frac{16}{19}$
(4)$\frac{12}{18}-\frac{7}{18}-\frac{3}{18}=$
$\frac{1}{9}$
(5)$\frac{8}{17}+\frac{9}{17}-\frac{8}{13}=$
$\frac{5}{13}$
(6)$\frac{11}{15}-\frac{13}{18}+\frac{4}{15}=$
$\frac{5}{18}$
答案
(1)
$\frac{2}{16} + \frac{7}{16} = \frac{2+7}{16} = \frac{9}{16}$
(2)
$\frac{10}{20} - \frac{6}{20} = \frac{10-6}{20} = \frac{4}{20} = \frac{1}{5}$
(3)
$\frac{3}{19} + \frac{8}{19} + \frac{5}{19} = \frac{3+8+5}{19} = \frac{16}{19}$
(4)
$\frac{12}{18} - \frac{7}{18} - \frac{3}{18} = \frac{12-7-3}{18} = \frac{2}{18} = \frac{1}{9}$
(5)
$\frac{8}{17} + \frac{9}{17} - \frac{8}{13} = \frac{8+9}{17} - \frac{8}{13} = 1 - \frac{8}{13} = \frac{5}{13}$
(6)
$\frac{11}{15} - \frac{13}{18} + \frac{4}{15} = \frac{11+4}{15} - \frac{13}{18} = 1 - \frac{13}{18} = \frac{5}{18}$
$\frac{2}{16} + \frac{7}{16} = \frac{2+7}{16} = \frac{9}{16}$
(2)
$\frac{10}{20} - \frac{6}{20} = \frac{10-6}{20} = \frac{4}{20} = \frac{1}{5}$
(3)
$\frac{3}{19} + \frac{8}{19} + \frac{5}{19} = \frac{3+8+5}{19} = \frac{16}{19}$
(4)
$\frac{12}{18} - \frac{7}{18} - \frac{3}{18} = \frac{12-7-3}{18} = \frac{2}{18} = \frac{1}{9}$
(5)
$\frac{8}{17} + \frac{9}{17} - \frac{8}{13} = \frac{8+9}{17} - \frac{8}{13} = 1 - \frac{8}{13} = \frac{5}{13}$
(6)
$\frac{11}{15} - \frac{13}{18} + \frac{4}{15} = \frac{11+4}{15} - \frac{13}{18} = 1 - \frac{13}{18} = \frac{5}{18}$
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