一、口算。
$23\% +19.8\% =$
$62.5\% ×\frac {4}{15}=$
$12.3+120\% =$
$105\% ÷5\% =$
$32.6×10\% =$
$1-35.5\% =$
$12×20\% =$
$23\% +19.8\% =$
0.428
$70÷35\% =$200
$39\% ×\frac {10}{13}=$$\frac{3}{10}$
$62.5\% ×\frac {4}{15}=$
$\frac{1}{6}$
$80\% -\frac {5}{7}=$$\frac{3}{35}$
$25\% ×5=$$\frac{5}{4}$
$12.3+120\% =$
13.5
$55\% ×\frac {7}{22}=$$\frac{7}{40}$
$1.3-27\% =$1.03
$105\% ÷5\% =$
21
$68\% ÷0.17=$4
$3.25\% ×4=$0.13
$32.6×10\% =$
3.26
$9.1÷7\% =$130
$90\% ×\frac {5}{12}=$$\frac{3}{8}$
$1-35.5\% =$
0.645
$20×50\% =$10
$50\% ÷0.4=$1.25
$12×20\% =$
$\frac{12}{5}$
$90\% ÷\frac {1}{9}=$8.1
$96\% -\frac {4}{5}=$0.16
答案
一、0.428 200 $\frac{3}{10}$
$\frac{1}{6}$ $\frac{3}{35}$ $\frac{5}{4}$
13.5 $\frac{7}{40}$ 1.03
21 4 0.13
3.26 130 $\frac{3}{8}$
0.645 10 1.25
$\frac{12}{5}$ 8.1 0.16
$\frac{1}{6}$ $\frac{3}{35}$ $\frac{5}{4}$
13.5 $\frac{7}{40}$ 1.03
21 4 0.13
3.26 130 $\frac{3}{8}$
0.645 10 1.25
$\frac{12}{5}$ 8.1 0.16
二、计算下面各题。
$(40\% +36.5\% )÷(90\% -75\% )$ $32×(75\% +50\% +12.5\% )$
$72×(1-25\% +\frac {1}{9})$ $120\% ×\frac {5}{6}+\frac {2}{3}×75\%$ $40\% ×[\frac {11}{21}÷(\frac {4}{7}-\frac {2}{9})]$
$(40\% +36.5\% )÷(90\% -75\% )$ $32×(75\% +50\% +12.5\% )$
$72×(1-25\% +\frac {1}{9})$ $120\% ×\frac {5}{6}+\frac {2}{3}×75\%$ $40\% ×[\frac {11}{21}÷(\frac {4}{7}-\frac {2}{9})]$
答案
1. 计算$(40\% + 36.5\%)÷(90\% - 75\%)$
解:
先计算括号内的值:
$40\%+36.5\% = 0.4 + 0.365=0.765$
$90\% - 75\%=0.9 - 0.75 = 0.15$
再计算除法:$0.765÷0.15 = 5.1$
2. 计算$32×(75\% + 50\% + 12.5\%)$
解:
先计算括号内的值:
$75\%+50\% + 12.5\%=0.75 + 0.5+0.125 = 1.375$
再计算乘法:$32×1.375 = 44$
3. 计算$72×(1 - 25\%+\frac{1}{9})$
解:
先计算括号内的值:
$1-25\%+\frac{1}{9}=1-\frac{1}{4}+\frac{1}{9}=\frac{3}{4}+\frac{1}{9}=\frac{27 + 4}{36}=\frac{31}{36}$
再计算乘法:$72×\frac{31}{36}=62$
4. 计算$120\%×\frac{5}{6}+\frac{2}{3}×75\%$
解:
先将百分数化为分数:$120\%=\frac{6}{5}$,$75\%=\frac{3}{4}$
则原式$=\frac{6}{5}×\frac{5}{6}+\frac{2}{3}×\frac{3}{4}$
$=1+\frac{1}{2}$
$=\frac{3}{2}=1.5$
5. 计算$40\%×[\frac{11}{21}÷(\frac{4}{7}-\frac{2}{9})]$
解:
先计算括号内的值:
$\frac{4}{7}-\frac{2}{9}=\frac{36 - 14}{63}=\frac{22}{63}$
再计算除法:$\frac{11}{21}÷\frac{22}{63}=\frac{11}{21}×\frac{63}{22}=\frac{3}{2}$
最后计算乘法:$40\%×\frac{3}{2}=\frac{2}{5}×\frac{3}{2}=\frac{3}{5}=0.6$
综上,答案依次为$5.1$;$44$;$62$;$1.5$;$0.6$。
解:
先计算括号内的值:
$40\%+36.5\% = 0.4 + 0.365=0.765$
$90\% - 75\%=0.9 - 0.75 = 0.15$
再计算除法:$0.765÷0.15 = 5.1$
2. 计算$32×(75\% + 50\% + 12.5\%)$
解:
先计算括号内的值:
$75\%+50\% + 12.5\%=0.75 + 0.5+0.125 = 1.375$
再计算乘法:$32×1.375 = 44$
3. 计算$72×(1 - 25\%+\frac{1}{9})$
解:
先计算括号内的值:
$1-25\%+\frac{1}{9}=1-\frac{1}{4}+\frac{1}{9}=\frac{3}{4}+\frac{1}{9}=\frac{27 + 4}{36}=\frac{31}{36}$
再计算乘法:$72×\frac{31}{36}=62$
4. 计算$120\%×\frac{5}{6}+\frac{2}{3}×75\%$
解:
先将百分数化为分数:$120\%=\frac{6}{5}$,$75\%=\frac{3}{4}$
则原式$=\frac{6}{5}×\frac{5}{6}+\frac{2}{3}×\frac{3}{4}$
$=1+\frac{1}{2}$
$=\frac{3}{2}=1.5$
5. 计算$40\%×[\frac{11}{21}÷(\frac{4}{7}-\frac{2}{9})]$
解:
先计算括号内的值:
$\frac{4}{7}-\frac{2}{9}=\frac{36 - 14}{63}=\frac{22}{63}$
再计算除法:$\frac{11}{21}÷\frac{22}{63}=\frac{11}{21}×\frac{63}{22}=\frac{3}{2}$
最后计算乘法:$40\%×\frac{3}{2}=\frac{2}{5}×\frac{3}{2}=\frac{3}{5}=0.6$
综上,答案依次为$5.1$;$44$;$62$;$1.5$;$0.6$。
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