一、将百分数改写成整数或小数(分数),将整数或小数(分数)改写成百分数。
$17.8\% =$
$500\% =$
$85\% = \frac{
$13.5\% = \frac{
$0.4\% =$
$1.2\% = \frac{
$360\% = \frac{
$150\% =$
$175\% = \frac{
$0.425= $
$\frac {1}{3}\approx $
$8.25= $
$30= $
$\frac {13}{2}= $
$\frac {11}{16}= $
$0.08= $
$\frac {27}{40}= $
$0.404= $
$17.8\% =$
0.178
$500\% =$
5
$85\% = \frac{
85
}{100
}$$13.5\% = \frac{
27
}{200
}$$0.4\% =$
0.004
$1.2\% = \frac{
3
}{250
}$$360\% = \frac{
18
}{5
}$$150\% =$
1.5
$175\% = \frac{
7
}{4
}$$0.425= $
42.5
$\% $$\frac {1}{3}\approx $
33.3
$\% $$8.25= $
825
$\% $$30= $
3000
$\% $$\frac {13}{2}= $
650
$\% $$\frac {11}{16}= $
68.75
$\% $$0.08= $
8
$\% $$\frac {27}{40}= $
67.5
$\% $$0.404= $
40.4
$\% $答案
解析:本题考查百分数与小数和分数的相互改写。
答案:
$17.8\% = 0.178$;
$500\% = 5$;
$85\% = \frac{85}{100}$;
$13.5\% = \frac{135}{1000}=\frac{27}{200}$;
$0.4\% = 0.004$;
$1.2\% = \frac{12}{1000}=\frac{3}{250}$;
$360\% = \frac{360}{100}=\frac{18}{5}$;
$150\% = 1.5$;
$175\% = \frac{175}{100}=\frac{7}{4}$;
$0.425 = 42.5\%$;
$\frac{1}{3} \approx 33.3\%$;
$8.25 = 825\%$;
$30 = 3000\%$;
$\frac{13}{2} = 6.5 = 650\%$;
$\frac{11}{16} = 0.6875 = 68.75\%$;
$0.08 = 8\%$;
$\frac{27}{40} = 0.675 = 67.5\%$;
$0.404 = 40.4\%$。
答案:
$17.8\% = 0.178$;
$500\% = 5$;
$85\% = \frac{85}{100}$;
$13.5\% = \frac{135}{1000}=\frac{27}{200}$;
$0.4\% = 0.004$;
$1.2\% = \frac{12}{1000}=\frac{3}{250}$;
$360\% = \frac{360}{100}=\frac{18}{5}$;
$150\% = 1.5$;
$175\% = \frac{175}{100}=\frac{7}{4}$;
$0.425 = 42.5\%$;
$\frac{1}{3} \approx 33.3\%$;
$8.25 = 825\%$;
$30 = 3000\%$;
$\frac{13}{2} = 6.5 = 650\%$;
$\frac{11}{16} = 0.6875 = 68.75\%$;
$0.08 = 8\%$;
$\frac{27}{40} = 0.675 = 67.5\%$;
$0.404 = 40.4\%$。
二、解方程。
$x÷\frac {5}{8}= \frac {10}{17}$
$6+\frac {7}{10}x= 10$
$\frac {2}{3}x-\frac {3}{5}x= 12$
$4x+\frac {1}{2}x= 9$
$4x+\frac {1}{9}= 5$
$\frac {5}{8}x= \frac {2}{5}+\frac {3}{5}$
$(1-\frac {1}{2})x= 14$
$2x-\frac {2}{7}x= \frac {2}{3}$
$\frac {5}{9}×\frac {9}{2}+\frac {1}{3}x= \frac {11}{4}$
$x÷\frac {5}{8}= \frac {10}{17}$
$6+\frac {7}{10}x= 10$
$\frac {2}{3}x-\frac {3}{5}x= 12$
$4x+\frac {1}{2}x= 9$
$4x+\frac {1}{9}= 5$
$\frac {5}{8}x= \frac {2}{5}+\frac {3}{5}$
$(1-\frac {1}{2})x= 14$
$2x-\frac {2}{7}x= \frac {2}{3}$
$\frac {5}{9}×\frac {9}{2}+\frac {1}{3}x= \frac {11}{4}$
答案
二、解方程。
1.
解:$x ÷ \frac{5}{8} = \frac{10}{17}$
$x = \frac{10}{17} × \frac{5}{8}$
$x = \frac{25}{68}$
2.
解:$6 + \frac{7}{10}x = 10$
$\frac{7}{10}x = 4$
$x = \frac{40}{7}$
3.
解:$\frac{2}{3}x - \frac{3}{5}x = 12$
$\frac{1}{15}x = 12$
$x = 180$
4.
解:$4x + \frac{1}{2}x = 9$
$\frac{9}{2}x = 9$
$x = 2$
5.
解:$4x + \frac{1}{9} = 5$
$4x = \frac{44}{9}$
$x = \frac{11}{9}$
6.
解:$\frac{5}{8}x = \frac{2}{5} + \frac{3}{5}$
$\frac{5}{8}x = 1$
$x = \frac{8}{5}$
7.
解:$(1 - \frac{1}{2})x = 14$
$\frac{1}{2}x = 14$
$x = 28$
8.
解:$2x - \frac{2}{7}x = \frac{2}{3}$
$\frac{12}{7}x = \frac{2}{3}$
$x = \frac{7}{18}$
9.
解:$\frac{5}{9} × \frac{9}{2} + \frac{1}{3}x = \frac{11}{4}$
$\frac{5}{2} + \frac{1}{3}x = \frac{11}{4}$
$\frac{1}{3}x = \frac{1}{4}$
$x = \frac{3}{4}$
1.
解:$x ÷ \frac{5}{8} = \frac{10}{17}$
$x = \frac{10}{17} × \frac{5}{8}$
$x = \frac{25}{68}$
2.
解:$6 + \frac{7}{10}x = 10$
$\frac{7}{10}x = 4$
$x = \frac{40}{7}$
3.
解:$\frac{2}{3}x - \frac{3}{5}x = 12$
$\frac{1}{15}x = 12$
$x = 180$
4.
解:$4x + \frac{1}{2}x = 9$
$\frac{9}{2}x = 9$
$x = 2$
5.
解:$4x + \frac{1}{9} = 5$
$4x = \frac{44}{9}$
$x = \frac{11}{9}$
6.
解:$\frac{5}{8}x = \frac{2}{5} + \frac{3}{5}$
$\frac{5}{8}x = 1$
$x = \frac{8}{5}$
7.
解:$(1 - \frac{1}{2})x = 14$
$\frac{1}{2}x = 14$
$x = 28$
8.
解:$2x - \frac{2}{7}x = \frac{2}{3}$
$\frac{12}{7}x = \frac{2}{3}$
$x = \frac{7}{18}$
9.
解:$\frac{5}{9} × \frac{9}{2} + \frac{1}{3}x = \frac{11}{4}$
$\frac{5}{2} + \frac{1}{3}x = \frac{11}{4}$
$\frac{1}{3}x = \frac{1}{4}$
$x = \frac{3}{4}$
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