计算下面各题。
$\frac {2}{11}+\frac {3}{11}+\frac {3}{11}$ $1-\frac {3}{5}-\frac {1}{5}$ $\frac {3}{14}+\frac {5}{14}+\frac {9}{14}$
$\frac {29}{37}-\frac {15}{37}-\frac {12}{37}$ $1-\frac {5}{24}-\frac {13}{24}$ $\frac {17}{32}+\frac {5}{32}+\frac {9}{32}$
$\frac {7}{8}-\frac {2}{3}+\frac {4}{3}$ $\frac {5}{12}+(\frac {2}{3}-\frac {1}{2})$ $\frac {5}{8}-(\frac {3}{4}-\frac {2}{3})$
$\frac {5}{6}-(\frac {1}{3}+\frac {3}{10})$ $\frac {17}{12}-\frac {3}{40}+\frac {1}{3}$ $2-\frac {2}{7}-\frac {3}{7}$
$\frac {2}{11}+\frac {3}{11}+\frac {3}{11}$ $1-\frac {3}{5}-\frac {1}{5}$ $\frac {3}{14}+\frac {5}{14}+\frac {9}{14}$
$\frac {29}{37}-\frac {15}{37}-\frac {12}{37}$ $1-\frac {5}{24}-\frac {13}{24}$ $\frac {17}{32}+\frac {5}{32}+\frac {9}{32}$
$\frac {7}{8}-\frac {2}{3}+\frac {4}{3}$ $\frac {5}{12}+(\frac {2}{3}-\frac {1}{2})$ $\frac {5}{8}-(\frac {3}{4}-\frac {2}{3})$
$\frac {5}{6}-(\frac {1}{3}+\frac {3}{10})$ $\frac {17}{12}-\frac {3}{40}+\frac {1}{3}$ $2-\frac {2}{7}-\frac {3}{7}$
答案
$\frac{8}{11}$ $\frac{1}{5}$ $\frac{17}{14}$ $\frac{2}{37}$ $\frac{1}{4}$ $\frac{31}{32}$ $\frac{23}{24}$ $\frac{7}{12}$ $\frac{13}{24}$
$\frac{1}{5}$ $\frac{67}{40}$ $1\frac{2}{7}$
$\frac{1}{5}$ $\frac{67}{40}$ $1\frac{2}{7}$
解方程。
$\frac {1}{2}+x= 1$ $x-\frac {3}{7}= \frac {1}{2}$ $x+\frac {2}{3}= \frac {7}{6}$
$x-\frac {5}{12}= \frac {3}{8}$ $x+\frac {2}{7}= \frac {3}{7}+\frac {1}{3}$ $x-(\frac {2}{3}+\frac {1}{4})= \frac {5}{6}$
$\frac {1}{2}+x= 1$ $x-\frac {3}{7}= \frac {1}{2}$ $x+\frac {2}{3}= \frac {7}{6}$
$x-\frac {5}{12}= \frac {3}{8}$ $x+\frac {2}{7}= \frac {3}{7}+\frac {1}{3}$ $x-(\frac {2}{3}+\frac {1}{4})= \frac {5}{6}$
答案
$x=\frac{1}{2}$ $x=\frac{13}{14}$ $x=\frac{1}{2}$ $x=\frac{19}{24}$ $x=\frac{10}{21}$
$x=\frac{7}{4}$
$x=\frac{7}{4}$
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