1.涂一涂,填一填。
(1)如图,涂出3 m²的$\frac{1}{6}$,涂色部分是多少平方米?

$(\quad)×\frac{(\quad)}{(\quad)}=\frac{(\quad)×(\quad)}{(\quad)}=\frac{(\quad)}{(\quad)}=\frac{(\quad)}{(\quad)}$
(2)右面这个长方形的面积是1 m²,先涂出$\frac{2}{3}$ m²,再涂出$\frac{2}{3}$ m²的$\frac{4}{5}$,涂色部分的面积是多少平方米?

$\frac{(\quad)}{(\quad)}×\frac{(\quad)}{(\quad)}=\frac{(\quad)×(\quad)}{(\quad)×(\quad)}=\frac{(\quad)}{(\quad)}$
(1)如图,涂出3 m²的$\frac{1}{6}$,涂色部分是多少平方米?
$(\quad)×\frac{(\quad)}{(\quad)}=\frac{(\quad)×(\quad)}{(\quad)}=\frac{(\quad)}{(\quad)}=\frac{(\quad)}{(\quad)}$
(2)右面这个长方形的面积是1 m²,先涂出$\frac{2}{3}$ m²,再涂出$\frac{2}{3}$ m²的$\frac{4}{5}$,涂色部分的面积是多少平方米?
$\frac{(\quad)}{(\quad)}×\frac{(\quad)}{(\quad)}=\frac{(\quad)×(\quad)}{(\quad)×(\quad)}=\frac{(\quad)}{(\quad)}$
答案
(1)(涂法不唯一)
$3×\frac{1}{6}=\frac{3×1}{6}=\frac{3}{6}=\frac{1}{2}$
(2)(涂法不唯一)
$\frac{2}{3}×\frac{4}{5}=\frac{2×4}{3×5}=\frac{8}{15}$
2.计算下面各题。
$2×\frac{1}{3}=$
$\frac{3}{4}×\frac{7}{12}=$
$\frac{7}{8}×\frac{4}{21}=$
$39×\frac{5}{13}=$
$\frac{10}{21}×\frac{3}{5}=$
$56×\frac{7}{8}=$
$15×\frac{5}{6}=$
$\frac{42}{55}×\frac{11}{35}=$
$2×\frac{1}{3}=$
$\frac{3}{4}×\frac{7}{12}=$
$\frac{7}{8}×\frac{4}{21}=$
$39×\frac{5}{13}=$
$\frac{10}{21}×\frac{3}{5}=$
$56×\frac{7}{8}=$
$15×\frac{5}{6}=$
$\frac{42}{55}×\frac{11}{35}=$
答案
$2×\frac{1}{3}=\frac{2}{3}$
$\frac{3}{4}×\frac{7}{12}=\frac{7}{16}$
$\frac{7}{8}×\frac{4}{21}=\frac{1}{6}$
$39×\frac{5}{13}=15$
$\frac{10}{21}×\frac{3}{5}=\frac{2}{7}$
$56×\frac{7}{8}=49$
$15×\frac{5}{6}=\frac{25}{2}$
$\frac{42}{55}×\frac{11}{35}=\frac{6}{25}$
$\frac{3}{4}×\frac{7}{12}=\frac{7}{16}$
$\frac{7}{8}×\frac{4}{21}=\frac{1}{6}$
$39×\frac{5}{13}=15$
$\frac{10}{21}×\frac{3}{5}=\frac{2}{7}$
$56×\frac{7}{8}=49$
$15×\frac{5}{6}=\frac{25}{2}$
$\frac{42}{55}×\frac{11}{35}=\frac{6}{25}$
3. 下面各题算得对吗?正确的画“√”,错误的画“×”,并改正。
(1) $15×\frac{3}{13}=\cancel{15}^5×\frac{\cancel{3}^1}{13}=\frac{5}{13}$ (
(2) $\frac{9}{14}×\frac{4}{9}=\frac{\overset{1}{\cancel{9}}}}{\underset{7}{\cancel{14}}}×\frac{\overset{2}{\cancel{4}}}}{\underset{1}{\cancel{9}}}=\frac{3}{8}$ (
(1) $15×\frac{3}{13}=\cancel{15}^5×\frac{\cancel{3}^1}{13}=\frac{5}{13}$ (
×
)(2) $\frac{9}{14}×\frac{4}{9}=\frac{\overset{1}{\cancel{9}}}}{\underset{7}{\cancel{14}}}×\frac{\overset{2}{\cancel{4}}}}{\underset{1}{\cancel{9}}}=\frac{3}{8}$ (
×
)答案
(1)× $15×\frac{3}{13}=\frac{15×3}{13}=\frac{45}{13}$
(2)× $\frac{9}{14}×\frac{4}{9}=\frac{\overset{1}{\cancel{9}}}{\underset{7}{\cancel{14}}}×\frac{\overset{2}{\cancel{4}}}{\underset{1}{\cancel{9}}}=\frac{2}{7}$
(2)× $\frac{9}{14}×\frac{4}{9}=\frac{\overset{1}{\cancel{9}}}{\underset{7}{\cancel{14}}}×\frac{\overset{2}{\cancel{4}}}{\underset{1}{\cancel{9}}}=\frac{2}{7}$
登录