1. 直接写出得数。(20☆)
$\frac{3}{4}×\frac{2}{5}=$
$\frac{1}{2}×8=$
$\frac{5}{6}×\frac{3}{10}=$
$4.2×\frac{2}{7}=$
$\frac{4}{9}×\frac{3}{8}=$
$\frac{7}{12}×\frac{4}{7}=$
$0.25×\frac{3}{5}=$
$\frac{5}{8}×\frac{4}{15}=$
$\frac{7}{10}×0.625=$
$\frac{9}{10}×\frac{5}{6}=$
$\frac{2}{3}×\frac{9}{4}=$
$0.36×\frac{5}{12}=$
$\frac{7}{8}×\frac{4}{7}=$
$\frac{5}{9}×\frac{3}{5}=$
$0.21×\frac{6}{7}=$
$\frac{3}{5}×\frac{10}{9}=$
$\frac{13}{15}×\frac{5}{26}=$
$4.8×\frac{7}{12}=$
$\frac{5}{6}×\frac{3}{4}=$
$\frac{8}{15}×\frac{5}{12}=$
$\frac{3}{4}×\frac{2}{5}=$
$\frac{1}{2}×8=$
$\frac{5}{6}×\frac{3}{10}=$
$4.2×\frac{2}{7}=$
$\frac{4}{9}×\frac{3}{8}=$
$\frac{7}{12}×\frac{4}{7}=$
$0.25×\frac{3}{5}=$
$\frac{5}{8}×\frac{4}{15}=$
$\frac{7}{10}×0.625=$
$\frac{9}{10}×\frac{5}{6}=$
$\frac{2}{3}×\frac{9}{4}=$
$0.36×\frac{5}{12}=$
$\frac{7}{8}×\frac{4}{7}=$
$\frac{5}{9}×\frac{3}{5}=$
$0.21×\frac{6}{7}=$
$\frac{3}{5}×\frac{10}{9}=$
$\frac{13}{15}×\frac{5}{26}=$
$4.8×\frac{7}{12}=$
$\frac{5}{6}×\frac{3}{4}=$
$\frac{8}{15}×\frac{5}{12}=$
答案
1. $\frac{3}{10}$,4,$\frac{1}{4}$,$\frac{6}{5}$
$\frac{1}{6}$,$\frac{1}{3}$,$\frac{3}{20}$,$\frac{1}{6}$
$\frac{7}{16}$,$\frac{3}{4}$,$\frac{3}{2}$,$\frac{3}{20}$
$\frac{1}{2}$,$\frac{1}{3}$,$\frac{9}{50}$,$\frac{2}{3}$
$\frac{1}{6}$,$\frac{14}{5}$,$\frac{5}{8}$,$\frac{2}{9}$
$\frac{1}{6}$,$\frac{1}{3}$,$\frac{3}{20}$,$\frac{1}{6}$
$\frac{7}{16}$,$\frac{3}{4}$,$\frac{3}{2}$,$\frac{3}{20}$
$\frac{1}{2}$,$\frac{1}{3}$,$\frac{9}{50}$,$\frac{2}{3}$
$\frac{1}{6}$,$\frac{14}{5}$,$\frac{5}{8}$,$\frac{2}{9}$
2. 先计算,再列出综合算式。(12☆)


综合算式:
综合算式:
综合算式:
$\frac{4}{5}-(0.8×\frac{3}{4})=\frac{1}{5}$
综合算式:
$(\frac{3}{4}-\frac{2}{5})×(\frac{3}{7}+\frac{2}{7})=\frac{1}{4}$
答案
2. $\frac{3}{5}$ $\frac{1}{5}$ $\frac{4}{5}-(0.8×\frac{3}{4})=\frac{1}{5}$
$\frac{7}{20}$ $\frac{5}{7}$ $\frac{1}{4}$ $(\frac{3}{4}-\frac{2}{5})×(\frac{3}{7}+\frac{2}{7})=\frac{1}{4}$
$\frac{7}{20}$ $\frac{5}{7}$ $\frac{1}{4}$ $(\frac{3}{4}-\frac{2}{5})×(\frac{3}{7}+\frac{2}{7})=\frac{1}{4}$
3. 计算下面各题,能简算的要简算。(18☆)
$\frac{5}{7}×14×\frac{3}{5}$
$(\frac{5}{6}+\frac{3}{4})×12$
$\frac{11}{13}×12+\frac{11}{13}$
$\frac{5}{12}×\frac{1}{4}+\frac{5}{12}×\frac{3}{4}$
$\frac{7}{10}×101-\frac{7}{10}$
$\frac{4}{5}×99+\frac{4}{5}$
$\frac{5}{7}×14×\frac{3}{5}$
$(\frac{5}{6}+\frac{3}{4})×12$
$\frac{11}{13}×12+\frac{11}{13}$
$\frac{5}{12}×\frac{1}{4}+\frac{5}{12}×\frac{3}{4}$
$\frac{7}{10}×101-\frac{7}{10}$
$\frac{4}{5}×99+\frac{4}{5}$
答案
3. 6 19 11 $\frac{5}{12}$ 70 80
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